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a: =-5/9-4/9+8/15+7/15-2/11=-2/11
b: =10/17+7/17-5/13-8/13+11/25
=11/25
c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8
d: =(31/10-25/10)*3-2
=3/5*3-2
=9/5-2
=-1/5
a) 10/17 - 5/13 -(-7)/17 - 8/13 + 11/25
=[10/17 + 7/17] - (5/13 + 3/13) + 11/25
=1-1+11/25 = 11/25
b) 4/20 + (-16)/42 - 6/15 + 3/-5 + 2/21 + 3/20 + (-10)/21
=(4/20+3/20) - (6/15+3/5) + (2/21+(-10)/21) + (-16)/42
=7/20 - 1 + (-8)/21 + (-16)/42
= -593/420
1: =72/90+65/90=137/90
2: =24/56-77/56=-53/56
3: =-7/10+4/5=1/10
4: =15/100-4/100=11/100
5: =4/6-5/6=-1/6
6: =10/40-15/40-76/40=-81/40
7: =-9/10+7/18
=-81/90+35/90=-46/90=-23/45
8: =27/90-55/90=-28/90=-14/45
9: =36/60-50/60-35/60=-49/60
10: =-4/9+5/6-3/8
=-32/72+60/72-27/72
=1/72
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
=7/38.(9/11+4/11-2/11)
=7/38
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
=5/31.(21/25-7/10-9/20)
=5/31.(-31/100)
=-1/20
Giải:
a) \(\left(9\dfrac{4}{9}+5\dfrac{2}{3}\right)-5\dfrac{1}{2}\)
\(=\left(\dfrac{85}{9}+\dfrac{17}{3}\right)-\dfrac{11}{2}\)
\(=\dfrac{136}{9}-\dfrac{11}{2}\)
\(=\dfrac{173}{18}\)
b) \(\dfrac{13}{9}.\dfrac{15}{4}-\dfrac{13}{9}.\dfrac{7}{4}-\dfrac{13}{9}.\dfrac{5}{4}\)
\(=\dfrac{13}{9}.\left(\dfrac{15}{4}-\dfrac{7}{4}-\dfrac{5}{4}\right)\)
\(=\dfrac{13}{9}.\dfrac{3}{4}\)
\(=\dfrac{13}{12}\)
c) \(\dfrac{2}{3}+\dfrac{5}{8}-\dfrac{-1}{3}+0,375\)
\(=\left(\dfrac{2}{3}-\dfrac{-1}{3}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)\)
\(=1+1\)
\(=2\)
d) \(75\%-3\dfrac{1}{2}+1,5:\dfrac{10}{7}\)
\(=\dfrac{3}{4}+\dfrac{7}{2}+\dfrac{3}{2}:\dfrac{10}{7}\)
\(=\dfrac{3}{4}+\dfrac{7}{2}+\dfrac{21}{20}\)
\(=\dfrac{53}{10}\)
e) \(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\dfrac{-47}{60}:\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\dfrac{-2}{5}\)
\(=1\)
\(\dfrac{4}{5}\)+\(\dfrac{-5}{4}\)=\(\dfrac{0}{4}\)
\(\dfrac{-1}{3}\)+\(\dfrac{2}{5}-\dfrac{5}{6}\)=\(\dfrac{-10}{30}+\dfrac{12}{30}-\dfrac{25}{30}\)=\(\dfrac{-23}{30}\)
\(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}\)=\(\dfrac{2}{3}-\dfrac{2}{5}\)=\(\dfrac{10}{15}-\dfrac{6}{15}\)=\(\dfrac{4}{15}\)
a: \(5-\dfrac{7}{8}+\dfrac{15}{-20}\)
\(=5-\dfrac{7}{8}-\dfrac{3}{4}\)
\(=\dfrac{5\cdot8-7-3\cdot2}{8}\)
\(=\dfrac{40-7-6}{8}=\dfrac{27}{8}\)
b: \(\dfrac{10}{-13}:\dfrac{-4}{13}\cdot\dfrac{11}{-10}\)
\(=-\dfrac{10}{13}\cdot\dfrac{13}{4}\cdot\dfrac{11}{10}\)
\(=-\dfrac{11}{4}\)
c: \(\dfrac{-3}{2}\cdot\dfrac{5}{2}+\dfrac{3}{-8}\)
\(=\dfrac{-15}{4}+\dfrac{-3}{8}\)
\(=\dfrac{-15\cdot2+\left(-3\right)}{8}=\dfrac{-33}{8}\)
d: \(\dfrac{7}{-8}-\dfrac{-4}{5}:\dfrac{3}{10}\)
\(=-\dfrac{7}{8}+\dfrac{4}{5}\cdot\dfrac{10}{3}\)
\(=-\dfrac{7}{8}+\dfrac{8}{3}\)
\(=\dfrac{-7\cdot3+8\cdot8}{24}=\dfrac{43}{24}\)
e: \(\dfrac{-5}{8}\cdot\dfrac{25}{111}+\dfrac{25}{111}\cdot\dfrac{3}{10}\)
\(=\dfrac{25}{111}\left(-\dfrac{5}{8}+\dfrac{3}{10}\right)\)
\(=\dfrac{25}{111}\cdot\dfrac{-25+12}{40}\)
\(=\dfrac{25}{40}\cdot\dfrac{-13}{111}=\dfrac{-5}{8}\cdot\dfrac{13}{111}=\dfrac{-65}{888}\)