Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1) 5 + (-4) = 1
2) (-8) + 2 = -6
3) 8 + (-2) = 6
4) 11 + (-3) = 8
5) (-11) + 2 = -9
6) (-7) + 3 = -4
7) (-5) + 5 = 0
8) 11 + (-12) = -1
9) (-18) + 20 = 2
10) (15) + (-12) = 3
11) (-17) + 17 = 0
12) 16 + (-2) = 14
13) (30) + (-14) = 16
14) (-19) + 20 = 1
15) (-18) + 15 = -3
16) (10) + (-6) = 4
17) (-28) + 14 = -14
18) 15 + (-30) = -15
19) (15) + (-4) = 11
20) (-21) + 11 = -10
21) 8 + (-22) = -14
22) (-15) + 4 = -11
23) (-3) + 2 = -1
24) 17 + (-14) = 3
25) 17 + (-14) = 3
=(1-1/4)(1-1/9)*...*(1-1/100^2)
=1/2*2/3*...*99/100*3/2*4/3*...*101/100
=1/100*101/2
=101/200
\(\left\{240-\left[76-\left(9-3\right)^2\right]\right\}:50\)
\(=\left[240-\left(76-6^2\right)\right]:50\)
\(=\left[240-\left(76-36\right)\right]:50\)
\(=\left(240-40\right):50\)
\(=200:50\)
\(=4\)
_______________
\(\dfrac{4^6\cdot3^4\cdot9^5}{6^{12}}\)
\(=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{6^{12}}\)
\(=\dfrac{2^{12}\cdot3^{14}}{2^{12}\cdot3^{12}}\)
\(=\dfrac{1\cdot3^2}{1\cdot1}\)
\(=3^2\)
\(=9\)
\(=300:\left[87-81-9\right]=300:\left(-3\right)=-100\)
a: (-3)+8-11
\(=\left(-3-11\right)+8\)
=-14+8
=-6
b: \(7-\left(-9\right)-3\)
=7+9-3
=16-3
=13
c: \(\left(-5\right)-\left(9-12\right)\)
\(=\left(-5\right)-\left(-3\right)\)
=-5+3
=-2
d: \(\left(-9\right)+\left(-1\right)-\left(-2\right)\)
\(=\left(-9-1\right)+2\)
=-10+2
=-8
e: \(\left(-3\right)+\left(-350\right)+\left(-6\right)\)
\(=-\left(3+350+6\right)\)
=-359
9. (–3) = – (|9| . |–3|) = –(9.3) = –27.