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Trả lời
568-{5.[143-3.(14-1)]+10}:10
=568-{5.[143-3.13]+10}:10
=568-{5.[143-39]+10}:10
=568-{5.104+10}:10
=568-530:10
=568-53
=515
568-{5x[143-3x13+10}:10
=568-{5x[143-39+10}:10
=568-(5x114):10
=568-570:10
=568-57
=511
`1,14 . 6,4 + 1,14 . 3,6 + 0,2 . 1,14 . 5`
`= 1,14 . (3,6 + 6,4 + 1)`
`= 1,14 . 11`
`= 12,54`
b)1024(5)-132(5)=892(5)
c)214(5).32(5)=6848(5)
d)211(5):13(5)=17(5)
2,1001(2):11(2)=91(2)
hehe làm bừa sai xin lỗivì tui ko hiểu
\(112\cdot35+112\cdot65+800\)
\(=112\cdot\left(35+65\right)+800\)
\(=112\cdot100+800\)
\(=11200+800\)
\(=12000\)
\(36:\left\{180:\left[2\cdot5^2-\left(5^3-3\cdot5\cdot7\right)\right]\right\}\)
\(=36:\left\{180:\left[2\cdot25-\left(125-15\cdot7\right)\right]\right\}\)
\(=36:\left\{180:\left[50-\left(125-105\right)\right]\right\}\)
\(=36:\left[180:\left(50-20\right)\right]\)
\(=36:\left(180:30\right)\)
\(=36:6\)
\(=6\)
\(=\dfrac{36}{180:\left[2\cdot25-5^3+15\cdot7\right]}=\dfrac{36}{180:30}=\dfrac{36}{6}=6\)
\(a.\frac{8}{7}+\frac{4}{7}\times\left(-\frac{6}{11}\right)-\frac{4}{7}\times\frac{5}{11}\)
\(=\frac{8}{7}+\frac{4}{7}\left(-\frac{6}{11}-\frac{5}{11}\right)\)
\(=\frac{8}{7}+\frac{4}{7}.\left(-1\right)\)
\(=\frac{8}{7}-\frac{4}{7}\)
\(=\frac{4}{7}\)