Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{\left(-5\right)^2.20^2}{8^2.125}=\dfrac{\left[\left(-5\right).20\right]^2}{2^{3^2}.5^3}=\dfrac{\left(-100\right)^2}{\text{4^3}.5^3}=\dfrac{10000}{\left(4.5\right)^3}=\dfrac{10000}{20^3}\dfrac{10000}{8000}=\dfrac{5}{4}\)
a. \(\frac{\left(-5\right)^2.20^4}{8^2.\left(-125\right)}=\frac{\left(-5\right)^2.5^4.2^8}{2^6.\left(-5\right)^3}=\left(-5\right)^3.2^2=\left(-125\right).4=-500\)
b, \(\frac{15^{11}.5^7.9^2}{5^{18}.27^6}=\frac{3^{11}.5^{11}.5^7.3^4}{5^{18}.3^{18}}=\frac{3^{15}.5^{18}}{5^{18}.3^{18}}=\frac{1}{3^3}=\frac{1}{27}\)
\(=\dfrac{11}{17}:\dfrac{19}{40}+\dfrac{11}{17}:\dfrac{23}{20}=\dfrac{11}{17}\cdot\left(\dfrac{40}{19}+\dfrac{20}{23}\right)=\dfrac{11}{17}\cdot\dfrac{1300}{437}=\dfrac{14300}{7429}\)
\(\left(\frac{2}{3}-\frac{4}{7}\right):\frac{5}{9}+\left(-\frac{8}{7}+\frac{1}{3}\right):\frac{5}{9}\)
\(=\left[\left(\frac{2}{3}-\frac{4}{7}\right)+\left(-\frac{8}{7}+\frac{1}{3}\right)\right]:\frac{5}{9}\)
\(=\left(\frac{2}{3}-\frac{4}{7}-\frac{8}{7}+\frac{1}{3}\right)\cdot\frac{9}{5}\)
\(=\left(1-\frac{12}{7}\right)\cdot\frac{9}{5}\)
\(=-\frac{5}{7}\cdot\frac{9}{5}\)
\(-\frac{9}{7}\)
\(\left(\frac{2}{3}-\frac{4}{7}\right):\frac{5}{9}+\left(-\frac{8}{7}+\frac{1}{3}\right):\frac{5}{9}\)
\(=\left(\frac{14}{21}-\frac{12}{21}\right):\frac{5}{9}+\left(-\frac{24}{21}+\frac{7}{21}\right):\frac{5}{9}\)
\(=\frac{2}{21}:\frac{5}{9}+\frac{-17}{21}:\frac{5}{9}\)
\(=\left(\frac{2}{21}+\frac{-17}{21}\right):\frac{5}{9}\)
\(=\frac{-15}{21}:\frac{5}{9}\)
\(=\frac{-15}{21}.\frac{9}{5}\)
\(=\frac{-9}{7}\)
\(=\frac{99}{35}\)
Mình ko ghi lại đề nha
=>(-1/5)2x5-(26x38/37x26)
=1/5-3
=-14/5
\(\frac{\left(-5\right)^2.20^4}{8^2.125}=\frac{25.20^4}{8^2.25.5}=\frac{20^4}{8^2.5}=500\)