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a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)
b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)
1. Tính hợp lí :
a) \(\frac{6}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
\(=\frac{5}{7}.\left(\frac{6}{11}+\frac{2}{11}-\frac{14}{11}\right)\)
\(=\frac{5}{7}.\frac{-6}{11}=-\frac{30}{77}\)
b) \(\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{1}{3}\)
\(\frac{1}{3}.\left(\frac{4}{5}+\frac{6}{5}-\frac{1}{3}\right)\)
\(=\frac{1}{3}.\frac{5}{3}=\frac{5}{9}\)
a.
\(\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{12}\right)+\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{5}{4}+\frac{3}{5}+\frac{3}{8}-\frac{7}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{12}{11}\right)\)
\(=\frac{-9}{10}\)
b.
\(\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{15}\right)+\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{3}{8}-\frac{7}{5}+\frac{5}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{15}{11}\right)\)
\(=\frac{-9}{8}\)
\(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1\)
\(=1\)
\(\frac{7}{9}-\frac{5}{12}+\frac{2}{9}-\frac{7}{12}\)
\(=\left(\frac{7}{9}+\frac{2}{9}\right)-\left(\frac{5}{12}+\frac{7}{12}\right)\)
\(=1-1\)
\(=0\)
các câu sau tương tự
A=1
B=0
C=ÂM 8/15
D=0
E=2
F=3/2
H=2/3
LẦN SAU CHO KHÓ SÍU NHA LỚP 5 CŨNG LÀM ĐC
1: \(B=75\%+1\dfrac{1}{5}\left(-1,25\right)+2\dfrac{1}{3}\)
\(=\dfrac{3}{4}+\dfrac{6}{5}\cdot\dfrac{-5}{4}+\dfrac{7}{3}\)
\(=\dfrac{3}{4}-\dfrac{6}{4}+\dfrac{7}{3}=\dfrac{7}{3}-\dfrac{3}{4}\)
\(=\dfrac{28}{12}-\dfrac{9}{12}=\dfrac{19}{12}\)
2: \(C=\left(\dfrac{2}{5}-\dfrac{5}{6}-\dfrac{2}{15}\right):\dfrac{8}{15}-\left(-\dfrac{1}{2}\right)^2\)
\(=\left(\dfrac{12}{30}-\dfrac{25}{30}-\dfrac{4}{30}\right)\cdot\dfrac{15}{8}-\dfrac{1}{4}\)
\(=\dfrac{-17}{30}\cdot\dfrac{15}{8}-\dfrac{1}{4}=\dfrac{-17}{16}-\dfrac{1}{4}=-\dfrac{17}{16}-\dfrac{4}{16}=-\dfrac{21}{16}\)
3: \(1\dfrac{5}{27}\cdot\left(-\dfrac{3}{2}\right)^2+\left(2,6-1\dfrac{3}{15}\right):\left(-\dfrac{3}{8}\right)\)
\(=\dfrac{32}{27}\cdot\dfrac{9}{4}+\left(2,6-1,2\right)\cdot\dfrac{-8}{3}\)
\(=\dfrac{8}{3}+1,4\cdot\dfrac{-8}{3}=\dfrac{8}{3}\cdot\left(1-1,4\right)=\dfrac{8}{3}\cdot\dfrac{-2}{5}=-\dfrac{16}{15}\)
4: \(A=\dfrac{3}{11}:\dfrac{4}{3}+\dfrac{8}{11}:\dfrac{4}{3}+\dfrac{1}{4}\)
\(=\left(\dfrac{3}{11}+\dfrac{8}{11}\right):\dfrac{4}{3}+\dfrac{1}{4}\)
\(=1:\dfrac{4}{3}+\dfrac{1}{4}=\dfrac{3}{4}+\dfrac{1}{4}=1\)
5: \(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{8}{5}\)
\(=\dfrac{28}{15}\cdot\dfrac{3}{4}-\left(0,55+0,25\right)\cdot\dfrac{5}{8}\)
\(=\dfrac{7}{5}-0,8\cdot\dfrac{5}{8}=\dfrac{7}{5}-\dfrac{8}{10}\cdot\dfrac{5}{8}=\dfrac{7}{5}-\dfrac{5}{10}=\dfrac{14}{10}-\dfrac{5}{10}=\dfrac{9}{10}\)
1)B=3/4+6/5*(-5/4)+7/3
=3/4+-3/2+7/3
=-3/4+7/3
=19/12
Bạn cần gấp thì m gui c1 trc ah