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\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)
\(\frac{0,75+0,6+\frac{3}{7}+\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)
\(=\frac{\frac{3}{4}+\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}+\frac{11}{5}-\frac{11}{7}-\frac{11}{13}}\)
\(=\frac{3\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}\)
Sai đề rồi bạn, đề thế thì giải ko đc, ra kết quả như trên ý
\(B=\left(0,75-0,6+\frac{3}{7}+\frac{3}{13}\right):\left(\frac{11}{7}+\frac{11}{13}+2,75-2,2\right)\)
\(B=\left(\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}\right):\left(\frac{11}{7}+\frac{11}{13}+\frac{11}{4}-\frac{11}{5}\right)\)
\(B=3\cdot\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right):11\cdot\left(\frac{1}{7}+\frac{1}{13}+\frac{1}{4}-\frac{1}{5}\right)\)
\(B=\frac{3}{11}\)
Hi Hi!
\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)\(=\frac{3}{11}\)
\(=\left(\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\right)\)
=\(\frac{3}{11}\)
a) Ta có: \(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}\)
\(=\frac{2.\left(0.2-\frac{1}{7}+\frac{1}{11}\right)}{3.\left(0,2-\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{2}{3}\)
b) Ta có: \(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
\(=\frac{3.\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}\)
\(=\frac{3}{11}\)
Chuk pạn hok tốt!
a) \(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}\\ =\frac{\frac{2}{5}-\frac{2}{7}+\frac{2}{11}}{\frac{3}{5}-\frac{3}{7}+\frac{3}{11}}\\ =\frac{2\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}{3\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}\\=\frac{2}{3}\)
b) \(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\\=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\\=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\\=\frac{3}{11}\)
\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
\(P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)
\(P=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}\)
\(P=\frac{3}{11}\)
\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
\(P=\frac{0,15+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,55+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)
\(P=\frac{0,05\times3+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,05\times11+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)
\(P=\frac{3\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}{11\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}\)
\(P=\frac{3}{11}\)
=3/11 nha bạn!. Có cần cách làm ko?
\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)