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58 x (3\(\frac{1}{29}\) - 2\(\frac{1}{58}\)) : \(\frac{1}{3}\)=
58 x 3 x ((3 - 2) + (\(\frac{1}{29}\)-\(\frac{1}{58}\))=
174 x (1 + (\(\frac{2}{58}\)- \(\frac{1}{58}\))) x 3 =
174 x (1 + \(\frac{1}{58}\)) =
174 + 174 x \(\frac{1}{58}\)=
174 + 3 = 177
\(58.\left(3\frac{1}{29}-2\frac{1}{58}\right):\frac{1}{3}\)
\(=58.\left(3\frac{2}{58}-2\frac{1}{58}\right).3\)
\(=58.\left[\left(3-2\right)+\left(\frac{2}{58}-\frac{1}{58}\right)\right].3\)
\(=58.\left[1+\frac{1}{58}\right].3\)
\(=58.\frac{59}{58}.3\)
\(=59.3\)
\(=177\)
Chúc bạn học tốt !!!
a ) \(-\frac{3}{7}.\frac{3}{11}+-\frac{3}{7}.\frac{8}{11}+1\frac{3}{7}\)
\(=-\frac{3}{7}.\left(\frac{3}{11}+\frac{8}{11}\right)+\frac{10}{7}\)
\(=-\frac{3}{7}.\frac{11}{11}+\frac{10}{7}\)
\(=-\frac{3}{7}.1+\frac{10}{7}\)
\(=\frac{10}{7}\)
b ) \(75\%.10,5=\frac{3}{4}.10,5=7,875\)
c ) \(5-3.\left(\left|-4\right|-30:15\right)\)
\(=5-3.\left(4-2\right)\)
\(=5-3.2\)
\(=5-6\)
\(=-1\)
d ) \(-\frac{5}{7}.\frac{2}{11}+-\frac{5}{7}.\frac{9}{11}+1\frac{5}{7}\)
\(=-\frac{5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=-\frac{5}{7}.1+\frac{12}{7}\)
\(=\frac{7}{7}\)
\(=1\)
Chúc bạn học tốt !!!
\(\left(\frac{37}{2}+\frac{43}{8}-\frac{173}{24}\right):\frac{50}{3}\)
\(=\left(\frac{444}{24}+\frac{129}{24}-\frac{173}{24}\right).\frac{3}{50}\)
\(=\frac{400}{24}.\frac{3}{50}\)
= 1
Chúc bạn làm bài tốt
Hỗn số phải ghi thế này chứ
c)\(\left(18\frac{1}{2}+5\frac{3}{8}-7\frac{5}{24}\right):16\frac{2}{3}\)
\(=\frac{50}{3}:\frac{50}{3}\)
\(=1\)
-10\(\frac15\) + 7\(\frac12\) + 3\(\frac14\)
= \(\frac{-51}{5}\) + \(\frac{15}{2}\) + \(\frac{13}{4}\)
= \(\frac{-204}{20}\) + \(\frac{150}{20}\) + \(\frac{65}{20}\)
= \(\frac{-54}{20}\) + \(\frac{65}{20}\)
= \(\frac{11}{20}\)
a) 5 8 . − 2 9 + 5 8 . − 7 9 + 1 1 3 . − 5 8 = 5 8 − 2 9 + − 7 9 + − 4 3 = − 35 24
b) 8 5 7 + 3 , 15 + 1 2 7 + 4 , 35 = 8 5 7 + 1 2 7 + ( 3 , 15 + 4 , 35 ) = 14 , 5
a) 5 8 . − 2 9 + 5 8 . − 7 9 + 1 1 3 . − 5 8 = 5 8 − 2 9 + − 7 9 + − 4 3 = − 35 24
b) 8 5 7 + 3 , 15 + 1 2 7 + 4 , 35 = 8 5 7 + 1 2 7 + 3 , 15 + 4 , 35 = 14 , 5
2/ \(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+\frac{29}{30}+\frac{41}{42}\)
\(=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+\left(1-\frac{1}{20}\right)+\left(1-\frac{1}{30}\right)+\left(1-\frac{1}{42}\right)\)
\(=\left(1+1+1+1+1+1\right)-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
\(=6-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)
\(=6-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(=6-\left(1-\frac{1}{7}\right)\)
\(=6-\frac{6}{7}=\frac{36}{7}\)
1, \(\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+\left(1-\frac{1}{20}\right)\)
\(=\left(1+1+1+1\right)-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\right)\)
\(=4-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}\right)\)
\(=4-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)\)
\(=4-\left(1-\frac{1}{5}\right)\)
\(=4-\frac{4}{5}=\frac{16}{5}\)
Giải:
58.(3\(\frac{1}{29}\) - 2\(\frac18\))
= 58.(\(\frac{88}{29}\) - \(\frac{17}{8}\))
= 58.\(\frac{88}{29}\) - 58.\(\frac{17}{8}\)
= 176 - \(\frac{493}{4}\)
= \(\frac{704}{4}\) - \(\frac{493}{4}\)
= \(\frac{211}{4}\)
52,75