Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
45 lần thừa số thứ 2 là
(6408 - 2403) : 45 = 89
số thứ 1 là
2403 : 89 = 27
vậy số thứ 1 là 27
số thứ 2 là 89
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gọi 2 số cần tìm là a, b
ta có a x b = 2403 ( 1)
và (a+ 45) x b = 6408
=> a x b+ b x 45 = 6408
(1) => 2403 + b x 45 = 6408
=> b x 45 = 6408- 2403
=> b x 45 = 4005
=> b= 89
(1) => a= 2403 : 89
=> a= 27
Tích cũ là: \(3\times45=135\)
Tích mới của hai số tăng thêm:
\(2\times45=90\)
Tích mới: \(5\times45=135+90=225\)
Tích của hai số sẽ tăng thêm:
2*45=90
Tích mới là 3*45+2*45=135+90=225
Thừa số giảm đi bao nhiêu lần thì tích cũng giảm đi bấy nhiêu lần
Nếu thừa số thứ nhất giảm đi 9 lần thì tích cũng sẽ giảm đi 9 lần
=> 45 : 9 = 5
Vậy, sau khi giảm thừa số thứ nhất đi 9 lần và giữ nguyên thừa số thứ 2, tích mới = 5