Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+....+1/19-1/20
A=1-1/20
A=20/20-1/20
A=19/20
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\ldots+\frac{1}{19\times20}+\frac{1}{20\times21}\)
\(=\frac11-\frac12+\frac12-\frac13+\frac14-\frac14+\ldots+\frac{1}{20}-\frac{1}{21}\)
\(=1-\frac{1}{21}\)
Vậy kết quả của phép tính trên là \(=\frac{20}{21}\)
A = \(\frac{1}{1\times2}\) + \(\frac{1}{2\times3}\) + \(\frac{1}{3\times4}\) + ... + \(\frac{1}{19\times20}\) + \(\frac{1}{20\times21}\)
A = \(\frac11\) - \(\frac12\) + \(\frac12\) - \(\frac13\) + \(\frac13\) - \(\frac14\) + ... + \(\frac{1}{19}\) - \(\frac{1}{20}\) + \(\frac{1}{20}\) - \(\frac{1}{21}\)
A = \(\frac11\) - \(\frac{1}{21}\)
A = \(\frac{20}{21}\)
Ta có: \(\frac{1}{1\times2}+\frac{1}{2\times3}+\cdots+\frac{1}{20\times21}\)
\(=1-\frac12+\frac12-\frac13+\cdots+\frac{1}{20}-\frac{1}{21}\)
\(=1-\frac{1}{21}=\frac{20}{21}\)
1/1x2 + 1/2×3 + 1/3×4 + 1/4×5 +....+ 1/18×19 + 1/19×20
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 +....+ 1/18 - 1/19 + 1/19 - 1/20
= 1 - 1/20
= 19/20
Bài 1:
Đặt \(A=\frac{2}{1x2}+\frac{2}{2x3}+\frac{2}{3x4}+...+\frac{2}{18x19}+\frac{2}{19x20}\)
\(\frac{A}{2}=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{18x19}+\frac{1}{19x20}\)
\(\frac{A}{2}=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+...+\frac{19-18}{18x19}+\frac{20-19}{19x20}\)
\(\frac{A}{2}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{2x19}{20}=\frac{19}{10}\)
Bài 2:
Đặt \(B=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{8x9}+\frac{1}{9x10}\)
Làm tương tự câu 1 có \(B=1-\frac{1}{10}=\frac{9}{10}\)
\(Bx100=\frac{9}{10}x100=90\)
=> \(\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=1\)
=> \(\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]=\frac{1}{2}\)
=> \(x+\frac{206}{100}=\frac{5}{2}:\frac{1}{2}=5\Rightarrow x=5-\frac{206}{100}=\frac{294}{100}=\frac{147}{50}\)
Ta thấy: \(\frac{1}{1.2}=\frac{2-1}{1.2}=\frac{2}{1.2}-\frac{1}{1.2}=1-\frac{1}{2}\); \(\frac{1}{2.3}=\frac{3-2}{2.3}=\frac{3}{2.3}-\frac{2}{2.3}=\frac{1}{2}-\frac{1}{3}\)
Tương tự với các phân số khác
Cho A=2/1x2 + 2/2x3 + 2/3x4 + 2/4x5 + ... + 2/19x20
=> \(A=2\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{18.19}+\frac{1}{19.20}\right)=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)
\(A=2\left(1-\frac{1}{20}\right)=2.\frac{19}{20}=\frac{19}{10}=1,9\)
Chú ý dấu chấm là dấu nhân
\(\frac{2}{1\times2}+\frac{2}{2\times3}+...+\frac{2}{19\times20}\)
\(=2\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{19}-\frac{1}{20}\right)\)
\(=2\times\left(1-\frac{1}{20}\right)=2\times\frac{19}{20}=\frac{19}{10}\)
1x2+2x3+...+19x20
3S= 1x2x3+2x3x3+3x4x3+...+19x20x3
3S=1x2x3+2x3x(4-1)+...+19x20x(21-3
3S=1x2x3+2x3x4-1x2x3+2x4x5-2x3x4+4x5x6+...19x20x21-18x19x20
S=19x20x21:3
S=7980
\(A=1\times2+2\times3+3\times4+...+19\times20\)
\(A\times3=3\times\left(1\times2+2\times3+3\times4+...+19\times20\right)\)
\(A\times3=1\times2\times3+2\times3\times3+3\times4\times3+...+19\times20\times3\)
\(A\times3=1\times2\times3+2\times3\times\left(4-1\right)+3\times4\times\left(5-2\right)+....+19\times20\times\left(21-18\right)\)
\(A\times3=1\times2\times3-1\times2\times3+2\times3\times4-2\times3\times4+3\times4\times5+...+19\times20\times21\)
\(A\times3=\left(1\times2\times3-1\times2\times3\right)+\left(2\times3\times4-2\times3\times4\right)+...+\left(18\times19\times20-18\times19\times20\right)+19\times20\times21\)
\(A\times3=19\times20\times21\)
\(A\times3=7980\)
cảm ơn bạn nhiều nhé