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a)= \(\frac{2}{3}+\frac{3}{2}.\frac{6}{5}-\frac{1}{5}\)
=\(\frac{13}{6}.1\)=\(\frac{13}{6}\)
b)= \(\frac{1}{9}.\frac{27}{2}-\frac{1}{5}:\frac{5}{6}\)
=\(\frac{3}{2}-\frac{6}{25}=\frac{63}{50}\)
\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)
a) \(10\sqrt{0,01}.\sqrt{\frac{16}{9}}+3\sqrt{49}-\frac{1}{6}\sqrt{4}\)
\(=10\sqrt{\frac{10}{100}}.\sqrt{\frac{4^2}{3^2}}+3.\sqrt{7^2}-\frac{1}{6}\sqrt{2^2}\)
\(=10.\frac{\sqrt{10}}{10}.\frac{4}{3}+3.7-\frac{1}{6}.2\)
\(=\frac{4\sqrt{10}}{3}+27-\frac{1}{3}\)
\(=\frac{4}{3}\sqrt{10}+\frac{80}{3}\)
b) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(0,8-\frac{3}{4}\right)^2\)
\(=\frac{17}{12}.\left(\frac{4}{5}-\frac{3}{4}\right)^2\)
\(=\frac{17}{12}.\left(\frac{1}{20}\right)^2\)
\(=\frac{17}{12}.\frac{1}{400}\)
\(=\frac{17}{4800}\)
\(\sqrt{\frac{9}{25}}+\sqrt{\frac{1}{6}}-\sqrt{\frac{4}{49}}\)\(=\sqrt{\left(\frac{3}{5}\right)^2}+\sqrt{\frac{1}{6}}-\sqrt{\left(\frac{2}{7}\right)^2}\)\(=\frac{3}{5}+\sqrt{\frac{1}{6}}-\frac{2}{7}\)\(=\left(\frac{3}{5}-\frac{2}{7}\right)+\sqrt{\frac{1}{6}}\)\(=\left(\frac{21}{35}-\frac{10}{35}\right)+\sqrt{\frac{1}{6}}\)\(=\frac{11}{35}+\sqrt{\frac{1}{6}}\)\(=\sqrt{\frac{1.6}{6.6}}+\frac{11}{35}\)\(=\frac{\sqrt{6}}{6}+\frac{11}{35}\)\(=\frac{35\sqrt{6}}{210}+\frac{66}{210}\)\(=\frac{35\sqrt{6}+66}{210}\)
=3/5+can1/6-2/7
=1,00824829-2/7
=0,722534004
sorry mình ko có can những số dài lắm