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x+1/3-4=-1
=>x+1/3=-1+4
=>x+1/3=3
=>x =3-1/3
=>x =8/3
Vậy x = 8/3
(2/25-1,008):4/7:(13/4-6/5/9)*36/17
=(2/25-126/125).7/4:(13/4-59/9)*36/17
=(10/125-126/125).7/4:(117/36-236/36)*36/17
=-116/125.7/4.(-36/119).36/17
=-203/125.(-1296/2023)=263088/252875
Mình tính ko nhanh đâu
a)\(\sqrt{9.4}=\sqrt{36}=6;\sqrt{9}.\sqrt{4}=3.2=6\Rightarrow\sqrt{9.4}=\sqrt{9}.\sqrt{4}\)
b)\(\sqrt{169-144}=\sqrt{25}=5;\sqrt{169}-\sqrt{144}=13-12=1\Rightarrow\sqrt{169-144}>\sqrt{169}-\sqrt{144}\)
tra loi ho mik lun di mai ik hoc roi !chut chut chuit chut
=3.74165738 chac 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%
\(\sqrt{9+25}=\sqrt{34}< \sqrt{36}=6\)
\(\sqrt{9}+\sqrt{25}=3+5=8>6\)
\(\Rightarrow\sqrt{9+25}< \sqrt{9}+\sqrt{25}\)
So sánh:\(\sqrt{9+25}\)và \(\sqrt{9}+\sqrt{25}\)
ta có: \(\sqrt{9+25}=\sqrt{34}\)
\(\sqrt{9}+\sqrt{25}=3+5=8=\sqrt{64}\)
Dễ thấy: \(\sqrt{34}< \sqrt{64}\)
Vậy: \(\text{ }\sqrt{9+25}< \sqrt{9}+\sqrt{25}\)
A= ( \(\sqrt{1}\)+\(\sqrt{2}\)+\(\sqrt{3}\) ) + (\(\sqrt{20}\) + \(\sqrt{40}\) + \(\sqrt{60}\))
= (1+1,4+1,7)+(4,4+6,3+7,7)
= 4,1+18,4
=22,5
Ta có\(\sqrt[3]{2}=1,25992105\\ \sqrt[2]{3}=1,732050808\)
=> 1,25992105<1,73205080 =>\(\sqrt[3]{2}< \sqrt[2]{3}\)