\(\dfrac{10^{2011}+1}{10^{2012}+1}và\dfrac{10^{2010}+1}{10^{2011}+1}\)

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9 tháng 2 2018

a/ Áp dụng bất đẳng thức :

\(\dfrac{a}{b}< 1\Leftrightarrow\dfrac{a}{b}< \dfrac{a+m}{b+m}\)

Ta có :

\(\dfrac{10^{2011}+1}{10^{2012}+1}< 1\)

\(\Leftrightarrow\dfrac{10^{2011}+1}{10^{2012}+1}< \dfrac{10^{2011}+1+9}{10^{2012}+1+9}=\dfrac{10^{2011}+10}{10^{2012}+10}=\dfrac{10\left(10^{2010}+1\right)}{10\left(10^{2011}+1\right)}=\dfrac{10^{2010}+1}{10^{2011}+1}\)

\(\Leftrightarrow\dfrac{10^{2011}+1}{10^{2012}+1}< \dfrac{10^{2010}+1}{10^{2011}+1}\)

9 tháng 2 2018

cho mn hỏi cái:\(\dfrac{10^{2011}+1}{10^{2012}+1}< \dfrac{10^{2011}+1+9}{10^{2012}+1+9}\)

2 tháng 3 2017

Vì \(\frac{10^{2011}+1}{10^{2012}+1}< 1\)

=> \(B=\frac{10^{2011}+1}{10^{2012}+1}< \frac{10^{2011}+1+9}{10^{2012}+1+9}=\frac{10^{2011}+10}{10^{2012}+10}=\frac{10\left(10^{2010}+1\right)}{10\left(10^{2011}+1\right)}=\frac{10^{2010}+1}{10^{2011}+1}=A\)

Vậy A > B

2 tháng 3 2017

A>B hay sao y

30 tháng 6 2018

a) Ta có :

\(A=\frac{10^{2010}+1}{10^{2011}+1}\)

\(\Rightarrow10A=\frac{10^{2011}+10}{10^{2011}+1}=\frac{\left(10^{2011}+1\right)+9}{10^{2011}+1}=1+\frac{9}{10^{2011}+1}\)

\(B=\frac{10^{2011}+1}{10^{2012}+1}\)

\(\Rightarrow10B=\frac{10^{2012}+10}{10^{2012}+1}=\frac{\left(10^{2012}+1\right)+9}{10^{2012}+1}=1+\frac{9}{10^{2012}+1}\)

Vì \(\frac{9}{10^{2011}+1}>\frac{9}{10^{2012}+1}\)nên \(10A>10B\)

\(\Rightarrow A>B\)

Vậy : \(A>B\)

b) Ta có :

\(\left(\frac{-1}{2}\right)^{11}=\frac{-1^{11}}{2^{11}}=\frac{-1}{2^{11}}\)

\(\left(\frac{-1}{2}\right)^{13}=\frac{-1^{13}}{2^{13}}=\frac{-1}{2^{13}}\)

Vì \(\frac{-1}{2^{11}}>\frac{-1}{2^{13}}\)nên \(\left(\frac{-1}{2}\right)^{11}>\left(\frac{-1}{2}\right)^{13}\)

Vậy : \(\left(\frac{-1}{2}\right)^{11}>\left(\frac{-1}{2}\right)^{13}\)

30 tháng 6 2018

\(B=\frac{10^{2011}+1}{10^{2012}+1}< \frac{10^{2011}+1+9}{10^{2012}+1+9}\)

\(B=\frac{10^{2011}+1}{10^{2012}+1}< \frac{10^{2011}+10}{10^{2012}+10}\)

\(B=\frac{10^{2011}+1}{10^{2012}+1}< \frac{10\cdot\left(10^{2010}+1\right)}{10\cdot\left(10^{2011}+1\right)}=\frac{10^{2010}+1}{10^{2011}+1}=A\)

Vậy : B < A

19 tháng 5 2017

Trước hết ta so sánh 10.A với 10.B từ đó ta \(\Rightarrow\) A < B. Ta có:

\(10.A=\dfrac{-10\left(10^{2011}+1\right)}{10^{2012}+1}=\dfrac{-\left(10^{2011}.10+10\right)}{10^{2012}+1}\)

\(=\dfrac{-\left(10^{2012}+10\right)}{10^{2012}+1}=\dfrac{-\left(10^{2012}+1\right)}{10^{2012}+1}-\dfrac{9}{10^{2012}+1}=-1-\dfrac{9}{10^{2012}+1}\)

Tương tự: \(10.B=-1-\dfrac{9}{10^{2013}+1}\)

Do \(10^{2013}+1>10^{2012}+1,\) nên \(\dfrac{-9}{10^{2013}+1}>\dfrac{-9}{10^{2012}+1}\)

Do đó \(10.A< 10.B,\) tức là \(A< B\)

5 tháng 7 2017

a) \(\frac{2^{10}+1}{2^{10}-1}\)và \(\frac{2^{10}-1}{2^{10}-3}\)

Ta có chính chất phân số trung gian là \(\frac{2^{10}+1}{2^{10}-3}\)

\(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}+1}{2^{10}-3}\) ; \(\frac{2^{10}-1}{2^{10}-3}< \frac{2^{10}+1}{2^{10}-3}\)

Vì \(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}+1}{2^{10}-3}>\frac{2^{10}-1}{2^{10}-3}\)

Nên \(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}-1}{2^{10}-3}\)

b) \(A=\frac{2011}{2012}+\frac{2012}{2013}\)và \(B=\frac{2011+2012}{2012+2013}\)

Ta có : \(A=\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{2013}+\frac{2012}{2013}=\frac{2011+2012}{2013}>\frac{2011+2012}{2012+2013}=B\)

Vậy A > B 

Có gì  sai cho sorry

a,

\(\frac{2^{10}+1}{2^{10}-1}=1+\frac{2}{2^{10}-1}< 1+\frac{2}{2^{10}-3}=\frac{2^{10}-1}{2^{10}-3}\)

b,

\(\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{2012+2013}+\frac{2012}{2012+2013}=\frac{2011+2012}{2012+2013}\)

12 tháng 6 2017

\(A=\dfrac{-9}{10^{2010}}+\dfrac{-19}{10^{2011}}=\dfrac{-90}{10^{2011}}+\dfrac{-19}{10^{2011}}=\dfrac{\left(-90\right)+\left(-19\right)}{10^{2011}}=\dfrac{-109}{10^{2011}}\)\(B=\dfrac{-9}{10^{2011}}+\dfrac{-19}{10^{2010}}=\dfrac{-9}{10^{2011}}+\dfrac{-190}{10^{2011}}=\dfrac{\left(-9\right)+\left(-190\right)}{10^{2011}}=\dfrac{-199}{10^{2011}}\)\(\text{Vì }\dfrac{-109}{10^{2011}}>\dfrac{-199}{10^{2011}}\text{ nên }A>B\)

16 tháng 3 2018

Ta có: \(A=\dfrac{-9}{10^{2010}}+\dfrac{-19}{10^{2011}}=\dfrac{-9}{10^{2010}}+\dfrac{-9}{10^{2011}}+\dfrac{-10}{10^{2011}}\)

\(B=\dfrac{-9}{10^{2011}}+\dfrac{-19}{10^{2010}}=\dfrac{-9}{10^{2011}}+\dfrac{-9}{10^{2010}}+\dfrac{-10}{10^{2010}}\)

So sánh A với B ta thấy: \(\dfrac{-9}{10^{2010}}=\dfrac{-9}{10^{2010}};\dfrac{-9}{10^{2011}}=\dfrac{-9}{10^{2011}}\)

\(\dfrac{-10}{10^{2011}}>\dfrac{-10}{10^{2010}}\)

\(\Rightarrow\) \(\dfrac{-9}{10^{2010}}+\dfrac{-9}{10^{2011}}+\dfrac{-10}{10^{2011}}>\dfrac{-9}{10^{2010}}+\dfrac{-9}{10^{2011}}+\dfrac{-10}{10^{2010}}\)

\(\Rightarrow\) \(A>B\)

Vậy A > B.

17 tháng 3 2018

Thanks