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Bài 1 :
a) ( x - 11 ) ( 2x - 16 ) = 0
\(\Rightarrow\orbr{\begin{cases}x-11=0\\2x-16=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=11\\x=8\end{cases}}\)
b) ( x + 1 ) ( x - 2 ) = 0
\(\Rightarrow\orbr{\begin{cases}x+1=0\\x-2=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=-1\\x=2\end{cases}}\)
c) x ( x + 1999 ) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x+1999=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=-1999\end{cases}}\)
Bài 2:
a: \(\dfrac{4\cdot7}{9\cdot32}=\dfrac{4}{32}\cdot\dfrac{7}{9}=\dfrac{1}{8}\cdot\dfrac{7}{9}=\dfrac{7}{72}\)
b: \(\dfrac{3\cdot21}{14\cdot15}=\dfrac{63}{210}=\dfrac{3}{10}\)
c: \(\dfrac{9\cdot6-9\cdot3}{18}=\dfrac{9\cdot3}{18}=\dfrac{3}{2}\)
d: \(\dfrac{17\cdot15-17}{3-20}=\dfrac{17\cdot14}{-17}=-14\)
e: \(=\dfrac{26\cdot5}{26\cdot35}=\dfrac{5}{35}=\dfrac{1}{7}\)
f: \(=\dfrac{49\left(1+7\right)}{49}=8\)
1/ \(444^{666}\)= \(4^{666}\).\(111^{666}\)=4096111.111666
\(666^{444}\)= \(6^{444}\). \(111^{444}\)= \(1296^{111}\).\(111^{444}\)
VÌ 4096 > 1296 =>\(4096^{111}\)> \(1296^{111}\); \(111^{666}\)> \(111^{444}\)
NÊN 4096111.111666 > \(1296^{111}\).\(111^{444}\)
=> \(444^{666}\)> \(666^{444}\)
A = \(\overline{1x,59}\) + \(\overline{5,y7}\) = 10,59 + \(x\) + 5.07 + \(\overline{0,y}\) = 15,66 + \(\overline{x,y}\) = B
Vậy A = B
a)x=(73)20=73.20=760
y=(72)20.7 28=72.20.728=740.728=768
Vi 60<68 nên 760<768
Hay( 73)20<(72)20.728