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a,Ta có: \(1-\frac{17}{19}=\frac{2}{19}\) và \(1-\frac{15}{17}=\frac{2}{17}\)
Vì \(\frac{2}{19}< \frac{2}{17}\) nên \(\frac{17}{19}< \frac{15}{17}\)
\(1-\dfrac{89}{90}=\dfrac{1}{90}\)
\(1-\dfrac{171}{172}=\dfrac{1}{172}\)
Vì \(\dfrac{1}{90}>\dfrac{1}{172}\Rightarrow\dfrac{89}{90}< \dfrac{171}{172}\)
Ta có:
\(1-\dfrac{63}{64}=\dfrac{1}{64}\)
\(1-\dfrac{105}{106}=\dfrac{1}{106}\)
VÌ \(\dfrac{1}{64}>\dfrac{1}{106}\Rightarrow\dfrac{63}{64}< \dfrac{105}{106}\)
63/64=1-1/64
105/106=1-1/106
mà -1/64<-1/106
nên 63/64<105/106
17/15>29/32
12/18<13/17
16/51>31/96
21/25>19/29>60/81
\(\frac{4}{6}=\frac{2}{3}\)
\(\frac{18}{27}=\frac{2}{3}\)
\(\Rightarrow\frac{4}{6}=\frac{18}{27}\)
\(\frac{12}{20}=\frac{3}{5}\)
\(\frac{22}{55}=\frac{2}{5}\)
\(\Rightarrow\frac{12}{20}>\frac{22}{55}\)
\(\frac{5}{6}=\frac{10}{12}\)
\(\Rightarrow\frac{5}{6}< \frac{11}{12}\)
Sắp xếp :
4;5;7;8;15;56
HT
\(\frac{4}{6}=\frac{2}{3}\)
\(\frac{18}{27}=\frac{2}{3}\)
\(\Rightarrow\frac{4}{6}=\frac{18}{27}\)
\(\frac{12}{20}=\frac{3}{5}\)
\(\frac{22}{55}=\frac{2}{5}\)
\(\Rightarrow\frac{12}{20}>\frac{22}{55}\)
\(\frac{5}{6}=\frac{10}{12}\)
\(\Rightarrow\frac{5}{6}< \frac{11}{12}\)
Sắp xếp:
4; 5; 7; 8; 15; 56.
_HT_
\(\frac{18}{19}=1-\frac{1}{19}\)
\(\frac{17}{18}=1-\frac{1}{18}\)
\(\frac{1}{19}< \frac{1}{18}\)
nên :
\(\frac{18}{19}>\frac{17}{18}\)
\(\frac{18}{19}=1-\frac{1}{19}\)
\(\frac{17}{18}=1-\frac{1}{18}\)
Vì \(\frac{1}{19}< \frac{1}{18}\) nên \(\frac{18}{19}>\frac{17}{18}\)