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bài3
1. \(\frac{4}{3}\)= \(\frac{4x4}{3x4}\)=\(\frac{20}{12}\)
\(\frac{3}{4}\)=\(\frac{3x3}{4x3}\)=\(\frac{9}{12}\)
2.\(\frac{5}{4}\)=\(\frac{5x6}{4x6}\)=\(\frac{30}{24}\)
\(\frac{5}{6}\)=\(\frac{5x4}{6x4}\)=\(\frac{20}{24}\)
3.\(\frac{3}{8}\)=\(\frac{3x6}{8x6}\)=\(\frac{18}{48}\)
\(\frac{1}{6}\)=\(\frac{1x6}{6x8}\)=\(\frac{6}{48}\)
4.\(\frac{2}{5}\)=\(\frac{2x7}{5x7}\)=\(\frac{14}{35}\)
\(\frac{4}{7}\)=\(\frac{4x5}{7x5}\)=\(\frac{20}{35}\)
Bài 1:
a)\(\frac{12}{33}\)\(< \)\(\frac{16}{33}\)(So sánh tử)
b) \(\frac{2}{5}\)=\(\frac{4}{10}\)\(>\)\(\frac{3}{10}\)(Quy đồng mẫu, so sánh tử)
Bài 2:
a)\(\frac{17}{24}+\frac{7}{24}=\frac{24}{24}=1\)
b) \(\frac{3}{5}+\frac{5}{3}=\frac{9}{15}+\frac{25}{15}=\frac{34}{15}\)
Bài 3:
a)\(\frac{7}{4}-\frac{3}{4}=\frac{4}{4}=1\)
b)\(\frac{21}{24}-\frac{6}{8}=\frac{21}{24}-\frac{18}{24}=\frac{3}{24}=\frac{1}{8}\)
\(a,\dfrac{1}{7}và\dfrac{4}{5}\)
\(\dfrac{1}{7}=\dfrac{1\times5}{7\times5}=\dfrac{5}{35}\)
\(\dfrac{4}{5}=\dfrac{4\times7}{5\times7}=\dfrac{28}{35}\)
Vậy \(\dfrac{5}{35}< \dfrac{28}{35}hay\dfrac{1}{7}< \dfrac{4}{5}\)
Ta có:
\(\frac{2}{5}=\frac{8}{20};\frac{4}{2}=\frac{40}{20};\frac{6}{2}=\frac{60}{20};\frac{9}{4}=\frac{45}{20};\frac{5}{4}=\frac{25}{20}\)
Vì \(\frac{8}{20}<\frac{25}{20}<\frac{40}{20}<\frac{45}{20}<\frac{60}{20}\) nên \(\frac{2}{5}<\frac{5}{4}<\frac{4}{2}<\frac{9}{4}<\frac{6}{2}\) và ngược lại:
\(\frac{6}{2}>\frac{9}{4}>\frac{4}{2}>\frac{5}{4}>\frac{2}{5}\)
a) \(\frac{6}{2}=3\) ; \(\frac{2}{5}\)không thể rút gọn
`MSC:36`
`5/12=(5xx3)/(12xx3)=15/36`
`4/9=(4xx4)/(9xx4)=16/36`
`-> 5/12 < 4/9`
`----`
`MSC:60`
`7/60` giữ nguyên
`1/5=(1xx12)/(5xx12)=12/60`
`->7/60<1/5`