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a) ta có \(\frac{1234}{1235}=1-\frac{1}{1235}\)
\(\frac{4319}{4320}=1-\frac{1}{4320}\)
vì \(\frac{1}{1235}>\frac{1}{4320}\Rightarrow1-\frac{1}{1235}< 1-\frac{1}{4320}\)
\(\Rightarrow\frac{1234}{1235}< \frac{4319}{4320}\)
b) ta có \(\frac{1234}{1244}=1-\frac{10}{1244}\)
\(\frac{4321}{4331}=1-\frac{10}{4331}\)
vì \(\frac{10}{1244}>\frac{10}{4331}\Rightarrow1-\frac{10}{1244}< 1-\frac{10}{4331}\)
\(\Rightarrow\frac{1234}{1244}< \frac{4321}{4331}\)
\(\Rightarrow\frac{-1234}{1244}>\frac{-4321}{4331}\)
a) \(\frac{1}{1235}>\frac{1}{4320}\Rightarrow-\frac{1}{1235}< -\frac{1}{4320}\Rightarrow1-\frac{1}{1235}< 1-\frac{1}{4320}\Rightarrow\frac{1234}{1235}< \frac{4319}{4320}.\)
b) \(\frac{10}{1244}< \frac{10}{4331}\Rightarrow\frac{10}{1244}-1< \frac{10}{4331}-1\Rightarrow-\frac{1234}{1244}< -\frac{4321}{4331}\)
a) Ta có:
1234/1235 = 1 - 1/1235
4319/4320 = 1 - 1/4320
Vì 1/1235 > 1/4320
=> 1234/1235 < 4319/4320
b) -1234/1244 = -1 + 10/1244
-4321/4331 = -1 + 10/4331
Vì 10/1244 > 10/4331
=> -1 + 10/4331 > -1/4331
Ủng hộ mk nha ♡_♡
31/32= 1 -1/32
31317/32327= 1- 1010/32327
ta có 1010/32327 x 32 = 32320/32327 <1=32/32=1/32 x 32
=> 1010/32327<1/32 => 31317/32327 > 31/32
Ta có\(\frac{-31}{-32}=\frac{31}{32}=\frac{31310}{32320}\)
Vì 31310<32320 nên \(\frac{31310}{32320}< 1\)
\(\Rightarrow\frac{31310}{32320}< \frac{31310+7}{32320+7}=\frac{31317}{32327}\)
\(\frac{-31}{-32}< \frac{31317}{32327}\)
Học tốt
b) Ta có:
\(\frac{1234.1235-1}{1234.1235}=1-\frac{1}{1234.1235}\)
\(\frac{1235.1236-1}{1235.1236}=1-\frac{1}{1235.1236}\)
DO \(\frac{1}{1234.1235}>\frac{1}{1235.1236}\)=> \(-\frac{1}{1234.1235}< -\frac{1}{1235.1236}\)
=> \(\frac{1234.1235-1}{1234.1235}< \frac{1235.1236-1}{1235.1236}\)
a) Ta có:
\(-\frac{31}{32}< 0< \frac{31317}{32327}\)
b) Ta có:
\(1-\frac{1234.1235-1}{1234.1235}=\frac{1}{1234.1235}\)
\(1-\frac{1235.1236-1}{1235.1236}=\frac{1}{1235.1236}\)
Mà \(\frac{1}{1234.1235}>\frac{1}{1235.1236}\)
\(\Rightarrow\frac{1234.1235-1}{1234.1235}< \frac{1235.1236-1}{1235.1236}\)
Ta có:\(\frac{-31}{-32}=\frac{31}{32}=\frac{31310}{32320}<\frac{31310+7}{32320+7}\)
Vì với P/S \(\frac{a}{b}\)
a<b=> \(\frac{a}{b}<\frac{a+m}{b+m}\left(m\in N,m\ne0\right)\)
Vậy \(\frac{-31}{-32}<\frac{31317}{32327}\)
mình mới học lớp 4 nên ko bít
em ko biết,xin lỗi chị nhiều lắm