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\(\frac{34}{43}< \frac{35}{42}\)
\(\frac{12}{48}< \frac{13}{47}\)
\(\frac{3}{7}>\frac{5}{14}\)
\(\frac{23}{48}< \frac{47}{92}\)
\(\frac{25}{30}>\frac{25}{49}\)
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\(\frac{25}{49}>\frac{25}{50}=\frac{1}{2}=\frac{35}{70}>\frac{35}{71}\)
Do đó \(\frac{25}{49}>\frac{35}{71}\).
\(\frac{1997}{2003}=\frac{2003-6}{2003}=1-\frac{6}{2003}\)
\(\frac{1995}{2001}=\frac{2001-6}{2001}=1-\frac{6}{2001}\)
Có \(\frac{6}{2003}< \frac{6}{2001}\)do đó \(\frac{1997}{2003}>\frac{1995}{2001}\).
\(\frac{2020}{2018}=\frac{2018+2}{2018}=1+\frac{2}{2018}< 1+\frac{2}{2016}=\frac{2018}{2016}\)
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a, Vì 15/25 > 13/25 .
Ta có : 15/25 = 3/5 = 3*7/5*7 = 21/35
vì 21>17 => 21/35 > 17/35 suy ra 13/25 > 17/35
Vậy 13/25 > 17/35
bn Trần Thanh Thảo bn trả lời cái thứ nhất còn cái thứ hai đâu bn?????
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ta có :\(\frac{12}{25}<\frac{12}{24}=\frac{1}{2}\Rightarrow\frac{12}{25}<\frac{1}{2}\left(1\right)\)
\(\frac{25}{49}>\frac{25}{50}=\frac{1}{2}\Rightarrow\frac{25}{49}>\frac{1}{2}\left(2\right)\)
Từ ( 1 ) và ( 2 ) \(\Rightarrow\frac{12}{25}<\frac{1}{2}<\frac{25}{49}\Rightarrow\frac{12}{25}<\frac{25}{49}\)
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Ta co
\(\frac{12}{25}<\frac{12}{24}=\frac{1}{2}\Rightarrow\frac{12}{25}<\frac{1}{2}\)(1)
\(\frac{25}{49}>\frac{25}{50}=\frac{1}{2}\Rightarrow\frac{25}{49}<\frac{1}{2}\left(2\right)\)
Tu \(\left(1\right)va\left(2\right)\Rightarrow\frac{25}{49}>\frac{1}{2}>\frac{12}{25}\Rightarrow\frac{25}{49}>\frac{12}{25}\)
25/35=5050/7070
25/35 = 5/7
5050/7070 = 5050 : 1010 / 7070 : 1010 = 5/7
---> 25/35 = 5050/7070
xin tiick