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\(\frac{7}{11}=\frac{120.7}{120.11}=\frac{840}{1320}\)
\(\frac{13}{20}=\frac{66.13}{66.20}=\frac{858}{1320}\)
\(\frac{2}{3}=\frac{440.2}{440.3}=\frac{880}{1320}\)
\(\frac{5}{8}=\frac{165.5}{165.8}=\frac{825}{1320}\)
vì \(\frac{825}{1320}<\frac{840}{1320}<\frac{858}{1320}<\frac{880}{1320}\)nên
\(\frac{5}{8}<\frac{7}{11}<\frac{13}{20}<\frac{2}{3}\)
nên sếp theo thứ tự từ bé đến lớn là
\(\frac{5}{8};\frac{7}{11};\frac{13}{20};\frac{2}{3}\)
a, theo thứ tự tăng dần là
-40,-29,0,13,27,32,36,/-35/
b, các số x (t/m) để -5_<x<6 là
-5,-4,-3,-2,-1,0,1,2,3,4,5,6
c, Ư(-8) là 1,-1,8,-8,2,-2,-4,4
\(\frac{5}{8}=\frac{75}{120}\)
\(-\frac{9}{10}=-\frac{108}{120}\)
\(\frac{7}{12}=\frac{70}{120}\)
\(-\frac{5}{6}=-\frac{100}{120}\)
\(-\frac{9}{10};-\frac{5}{6};\frac{7}{12};\frac{5}{8}\)
a) - 17 ; - 2 ; 0 ; 1 ; 2 ; 5
b) 2001 ; 15 ; 7 ; 0 ; - 8 ; - 101
a,\(=\frac{-5}{9}+\frac{8}{15}+\frac{-2}{11}+\frac{-4}{9}+\frac{7}{15}\)
\(\left(\frac{-5}{9}+\frac{-4}{9}\right)+\left(\frac{8}{15}+\frac{7}{15}\right)+\frac{-2}{11}\)
=-1+1+-2/11
=0+-2/11
=-2/11
b,\(=\left(\frac{5}{13}+\frac{8}{13}\right)+\left(\frac{-20}{41}+\frac{-21}{40}\right)+\frac{-5}{17}\)
=1+-1+-5/17
=0+-5/17
=-5/17
c,\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{-2}{9}+-\frac{7}{9}\right)+\frac{16}{17}\)
=1+-1+16/17
=0+16/17
=16/17
d,\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{99}-\frac{1}{101}\)
\(=\frac{1}{3}-\frac{1}{101}=\frac{98}{303}\)
a.\(\frac{-5}{9}\)+\(\frac{8}{15}\)+\(\frac{-2}{11}\)+\(\frac{4}{-9}\)+\(\frac{7}{15}\)
=\(\frac{-5}{9}\)+\(\frac{4}{-9}\)+\(\frac{8}{15}\)+\(\frac{7}{15}\)+\(\frac{-2}{11}\)
=(\(\frac{-5}{9}\)+\(\frac{-4}{9}\))+(\(\frac{8}{15}\)+\(\frac{7}{15}\))+\(\frac{-2}{11}\)
=(-1)+1+\(\frac{-2}{11}\)
=0+\(\frac{-2}{11}\)
=\(\frac{-2}{11}\).
a) Ta có:
\(\dfrac{7}{11}=0,\left(63\right)\)
\(\dfrac{8}{-13}=-0,\left(615384\right)\)
\(\dfrac{37}{19}\approx1,95\)
\(\dfrac{-5}{13}=-0,\left(384615\right)\)
\(\Rightarrow-0,\left(615384\right)< -0,\left(384615\right)< 0< 0,\left(63\right)< 1,95\)
\(\Rightarrow\dfrac{8}{-13}< \dfrac{-5}{13}< 0< \dfrac{7}{11}< \dfrac{37}{19}\)
b) Ta có:
\(\dfrac{-9}{17}\approx-0,53\)
\(-\dfrac{6}{5}=-1,2\)
\(\dfrac{7}{-17}\approx-0,41\)
\(\Rightarrow-3,4< -1,2< -1,02< -0,53< -0,41< 0\)
\(\Rightarrow-3,4< -\dfrac{6}{5}< -1,02< \dfrac{-9}{17}< \dfrac{7}{-17}< 0\)
a: 0<7/11
7/11<1
1=19/19<37/19
=>0<7/11<37/19
mà -8/13<-5/13<0
nên -8/13<-5/13<0<7/11<37/19
b: -1<-9/17<-7/17<0
-3,4<-1,2=-6/5<-1,02<-1
Do đó: -3,4<-6/5<-1,02<-1<-9/17<-7/17<0