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9 tháng 8 2016
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}-\frac{1}{26}+...+\frac{1}{61}-\frac{1}{66}\)
\(=\frac{1}{11}-\frac{1}{66}=\frac{6}{66}-\frac{1}{66}=\frac{5}{66}\)
BM
0
LM
0
MH
10 tháng 1 2016
a. \(C=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
\(=\frac{1}{11}-\frac{1}{66}=\frac{5}{66}\)
b. \(D=\frac{2}{3}.\left(\frac{3}{1.4}+\frac{4}{4.7}+...+\frac{3}{97.100}\right)\)
\(=\frac{2}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{100}\right)\)
\(=\frac{2}{3}.\left(1-\frac{1}{100}\right)=\frac{2}{3}.\frac{99}{100}=\frac{33}{50}\)
10 tháng 1 2016
\(C=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-....-\frac{1}{66}\)
\(C=\frac{1}{11}-\frac{1}{66}=\frac{5}{66}\)
\(D=\frac{2}{3}.\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-....-\frac{1}{100}\right)\)
\(D=\frac{2}{3}.\left(1-\frac{1}{100}\right)=\frac{2}{3}.\frac{99}{100}=\frac{33}{50}\)
DD
1
HH
7
15 tháng 7 2017
\(A=\dfrac{5}{11.16}+\dfrac{5}{16.21}+\dfrac{5}{21.26}+...............+\dfrac{5}{61.66}\)
\(\Leftrightarrow A=\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+............+\dfrac{1}{61}-\dfrac{1}{66}\)
\(\Leftrightarrow A=\dfrac{1}{11}-\dfrac{1}{66}=\dfrac{5}{66}\)
LG
15 tháng 7 2017
\(A=\dfrac{5}{11\times16}+\dfrac{5}{16\times21}+\dfrac{5}{21\times26}+...+\dfrac{5}{61\times66}\)
\(=\dfrac{1}{11}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{21}+\dfrac{1}{21}-\dfrac{1}{26}+...+\dfrac{1}{61}-\dfrac{1}{66}\)
\(=\dfrac{1}{11}-\dfrac{1}{66}\)
\(=\dfrac{5}{66}\)
~ Học tốt ~
BD
7
28 tháng 5 2018
\(\frac{5}{11.16}+\frac{5}{16.21}+..+\frac{5}{36.41}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+..+\frac{1}{36}-\frac{1}{41}\)
\(=\frac{1}{11}-\frac{1}{41}\)
= bn tự timnhs nha......................................
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28 tháng 5 2018
\(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{36.41}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{36}-\frac{1}{41}\)
\(=\frac{1}{11}-\frac{1}{41}\)
\(=\frac{30}{451}\)
_Chúc bạn học tốt_
ES
3
17 tháng 7 2016
R = 5 / 11 * 16 + 5 / 16 * 21 + ...+ 5 / 61 * 66
= 1/11 - 1/16 + 1/16 - 1/21 + ... + 1/61 - 1/66
= 1/11 - 1/66
= 5/66
17 tháng 7 2016
\(R=\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\)
\(R=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
\( R=\frac{1}{11}-\frac{1}{66}=\frac{6}{66}-\frac{1}{66}=\frac{5}{66}\)
TH
2
30 tháng 4 2019
52/1*6 + 52/6*11 + 52/11*16 + 52/16*21 + 52/21*26 + 52/26*31
=5(1-1/6+1/6-1/11+1/11-...+1/26-1/31)
=5(1-1/31)
=5.30/31
=150/31
30 tháng 4 2019
52/1 x 6 + 52/6 x 11 + 52/11 x 16 + 52/16 x 21 + 52/21 x 26 + 52/26 x 31
= 5.(5/1.6 + 5/6.11 + 5/11.16 + 5/16.21 + 5/21.26 + 5/26.31)
= 5.(1 - 1/6 + 1/6 - 1/11 + 1/11 - 1/16 + 1/16 - 1/21 + 1/21 - 1/26 + 1/26 - 1/31)
= 5.(1 - 1/31)
= 5.30/31
= 150/31
NN
29 tháng 7 2016
a)\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
b)\(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\)
\(=\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+....+\frac{1}{61}-\frac{1}{66}\)
\(=\frac{1}{11}-\frac{1}{66}\)
\(=\frac{5}{66}\)
29 tháng 7 2016
a,\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
ta có:
\(\frac{1}{1.2}=\frac{2-1}{1.2}=\frac{2}{1.2}-\frac{1}{1.2}=1-\frac{1}{2}\)
\(\frac{1}{2.3}=\frac{3-2}{2.3}=\frac{3}{2.3}-\frac{2}{2.3}=\frac{1}{2}-\frac{1}{3}\)
...
\(\frac{1}{99.100}=\frac{1}{99}-\frac{1}{100}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
=\(1-\frac{1}{100}=\frac{99}{100}\)
b,
\(\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.16}+...+\frac{5}{61.66}\)
ta có:
\(\frac{5}{11.16}=\frac{16-11}{11.16}=\frac{16}{11.16}-\frac{11}{11.16}=\frac{1}{11}-\frac{1}{16}\)
\(\frac{5}{16.21}=\frac{21-16}{16.21}=\frac{21}{16.21}-\frac{16}{16.21}=\frac{1}{16}-\frac{1}{21}\)
...
\(\frac{5}{61.66}=\frac{66-61}{61.66}=\frac{66}{61.66}-\frac{61}{61.66}=\frac{1}{61}-\frac{1}{66}\)
= \(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
=\(\frac{1}{11}-\frac{1}{66}\)=\(\frac{5}{66}\)