Question

[Ru Bakaa]

Rút gọn:

\(a,\dfrac{2ax^2-4ax+2a}{5b-5bx^2}\)

\(b,\dfrac{\left(x+y^2\right)-z^2}{x+y+z}\)

Answer 1

[Nguyen My Van]

\(a,\dfrac{2ax^2-4ax+2a}{5b-5bx^2}\)

\(=\dfrac{2a\left(x^2-2x+1\right)}{5b\left(1-x^2\right)}\)

\(=\dfrac{2a\left(x-1^2\right)}{5b\left(x-1\right)\left(1+x\right)}\)

\(=\dfrac{2a\left(x-1\right)}{5b\left(x+1\right)}\)

\(b,\dfrac{\left(x+y\right)^2-z^2}{x+y+z}\)

\(=\dfrac{\left(x+y-z\right)\left(x+y+z\right)}{x+y+z}=x+y-z\)