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1 tháng 6 2020

\(B=\frac{25^5+25^7+25^9}{5^{11}+5^{13}+5^{15}+5^{17}+5^{19}+5^{21}}\)

\(B=\frac{\left(5^2\right)^5+\left(5^2\right)^7+\left(5^2\right)^9}{5^{11}+5^{13}+5^{15}+5^{17}+5^{19}+5^{21}}\)

\(B=\frac{5^{10}+5^{14}+5^{18}}{5^{11}+5^{13}+5^{15}+5^{17}+5^{19}+5^{21}}\)

\(B=\frac{5^{10}.\left(1+5^4+5^8\right)}{5^{11}.\left(1+5^2+5^4+5^6+5^8+5^{10}\right)}\)

\(B=\frac{1+5^4+5^8}{5.\left[\left(1+5^4+5^8\right)+5^2.\left(1+5^4+5^8\right)\right]}\)

\(B=\frac{1+5^4+5^8}{5.\left[\left(1+5^4+5^8\right).\left(1+5^2\right)\right]}\)

\(B=\frac{1+5^4+5^8}{5.\left(1+5^4+5^8\right).26}\)

\(B=\frac{1}{5.26}\)

\(B=\frac{1}{130}\)

Nhớ k cho m nha 

5 tháng 3 2019

a)\(\frac{25-7.25}{6.15}\)

\(=\frac{25.\left(1-7\right)}{6.15}\)

\(=\frac{25.\left(-6\right)}{6.15}\)

\(=\frac{5.\left(-1\right)}{1.3}\)

\(=\frac{-5}{3}\)

b)\(\frac{15.11-15}{25.\left(-10\right)}\)

\(=\frac{15.\left(11-1\right)}{25.\left(-10\right)}\)

\(=\frac{15.10}{25.\left(-10\right)}\)

\(=\frac{3.1}{5.\left(-1\right)}\)

\(=\frac{-3}{5}\)

5 tháng 3 2019

Ok thanks bn

cho bn 3

Hi

12 tháng 3 2017

\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}....\frac{899}{900}\)

\(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}....\frac{29.31}{30.30}\)

\(=\frac{1.2.3....29}{2.3.4....30}.\frac{3.4.5....31}{2.3.4....30}\)

\(=\frac{1}{30}.\frac{31}{2}=\frac{31}{60}\)

12 tháng 3 2017

\(A=\frac{1\cdot3}{2\cdot2}\cdot\frac{2\cdot4}{3\cdot3}\cdot...\cdot\frac{29\cdot31}{30\cdot30}\)

\(A=\frac{1\cdot2\cdot...\cdot29}{2\cdot3\cdot...\cdot30}\cdot\frac{3\cdot4\cdot...\cdot31}{2\cdot3\cdot...\cdot30}=\frac{1}{30}\cdot\frac{31}{2}=\frac{31}{60}\)

2 tháng 3 2016

\(A=\frac{25^{28}+25^{24}+25^{20}+...+25^4+1}{25^{30}+25^{28}+25^{26}+...+25^2+1}=25^{30}+25^{26}+25^{22}+25^{18}+25^{14}+25^{10}+25^6+25^2\)

13 tháng 3 2015

cho 1 cai dung minh cho ban roi ma

10 tháng 7 2016

a.

\(\frac{5^3\times90\times4^3}{25^2\times3^2\times2^{13}}=\frac{5^3\times5\times9\times2\times\left(2^2\right)^3}{\left(5^2\right)^2\times3^2\times2^{13}}=\frac{5^4\times3^2\times2\times2^6}{5^4\times3^2\times2^{13}}=\frac{1}{2^6}=\frac{1}{64}\)

b.

\(\frac{18\times27+18\times\left(-23\right)}{34\times4-4\times52}=\frac{18\times\left(27-23\right)}{4\times\left(34-52\right)}=\frac{18\times4}{4\times\left(-18\right)}=-1\)

c.

\(\frac{15^2\times16^4-15^3\times16^3}{12^2\times20^3-20^2\times12^3}=\frac{16^3\times15^2\times\left(16-15\right)}{12^2\times20^2\times\left(20-12\right)}=\frac{16\times\left(16\times15\right)^2}{8\times\left(20\times12\right)^2}=\frac{16\times240^2}{8\times240^2}=2\)

d.

\(\frac{2\times3+4\times6+14\times21}{3\times5+6\times10+21\times35}=\frac{2\times3\times\left(1+2\times2+7\times7\right)}{3\times5\times\left(1+2\times2+7\times7\right)}=\frac{2}{5}\)

Chúc bạn học tốtok

10 tháng 7 2016

a) \(\frac{5^3\cdot90\cdot4^3}{25^2\cdot3^2\cdot2^{13}}=\frac{5^3\cdot2\cdot3^2\cdot5\cdot2^6}{5^4\cdot3^2\cdot2^{13}}=\frac{1}{2^6}=\frac{1}{64}\)

b) \(\frac{18\cdot27+18\cdot\left(-23\right)}{34\cdot4-4\cdot52}=\frac{18\left(27-23\right)}{4\left(34-52\right)}=\frac{9\cdot4}{2\cdot\left(-18\right)}=\frac{3^2\cdot2^2}{2\cdot2\cdot3^2\cdot\left(-1\right)}=-1\)

c) \(\frac{15^2\cdot16^4-15^3\cdot16^3}{12^2\cdot20^3-20^2\cdot12^3}=\frac{15^2\cdot16^3\left(16-15\right)}{12^2\cdot20^2\left(20-12\right)}=\frac{15^2\cdot16^3}{12^2\cdot20^2\cdot8}=\frac{3^2\cdot5^2\cdot2^{12}}{2^4\cdot3^2\cdot2^4\cdot5^2\cdot2^3}=2\)

d) \(\frac{2\cdot3+4\cdot6+14\cdot21}{3\cdot5+6\cdot10+21\cdot35}=\frac{2\cdot3+2^2\cdot2\cdot3+2\cdot3\cdot7^2}{3\cdot5+2^2\cdot3\cdot5+3\cdot5\cdot7^2}=\frac{2\cdot3\left(1+2^2+7^2\right)}{3\cdot5\left(1+2^2+7^2\right)}=\frac{2}{5}\)

25 tháng 5 2016

\(A=\frac{3x8x15x24x.....x899}{4x9x16x25x.....x900}\)

25 tháng 5 2016

A=3/4x8/9x15/16x24/25x...x899/900

A=1.3/22 x 2.4/33 x 3.5/42 x 4.6/55 x ... x 29.31/302

A=1.2.3.4...29/2.3.4.5...30 x 3.4.5.6...31/2.3.4.5...30

A=1/30 x 31/2

A=31/60