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6 tháng 11 2021
\(\frac{5^{32}.20^{43}}{\left(-8\right)^{29}.125^{25}}\)
\(=\frac{5^{32}.\left(2^2.5\right)^{43}}{\left\{\left(-2\right)^3\right\}^{29}.\left(5^3\right)^{25}}\)
\(=\frac{5^{32}.2^{86}.5^{43}}{\left(-2\right)^{87}.5^{75}}\)
\(=\frac{5^{75}.2^{86}}{\left(-2\right).2^{86}.5^{75}}\)
\(=\frac{1}{-2}=-\frac{1}{2}\)
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