Câu hỏi của Nguyễn Thanh Hiền

Question

Rut gon tong sau

C=1+2^2+2^4+....+2^2008

Phương An · Accepted Answer

$C=1+2^2+2^4+...+2^{2008}$

$4C=2^2+2^4+2^6+...+2^{2010}$

$4C-C=\left(2^2+2^4+2^6+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)$

$3C=2^{2010}-1$

$C=\frac{2^{2010}-1}{3}$

Câu trả lời:

$C=1+2^2+2^4+...+2^{2008}$

$4C=2^2+2^4+2^6+...+2^{2010}$

$4C-C=\left(2^2+2^4+2^6+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)$

$3C=2^{2010}-1$

$C=\frac{2^{2010}-1}{3}$

Võ Đông Anh Tuấn · Answer

$C=1+2^2+2^4+...+2^{2008}$

$\Rightarrow4C=2^2+2^4+...+2^{2010}$

$\Rightarrow4C-C=\left(2^2+2^4+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)$

$\Rightarrow3C=2^{2010}-1$

$\Rightarrow C=\frac{2^{2010}-1}{3}$

Câu trả lời:

$C=1+2^2+2^4+...+2^{2008}$

$\Rightarrow4C=2^2+2^4+...+2^{2010}$

$\Rightarrow4C-C=\left(2^2+2^4+...+2^{2010}\right)-\left(1+2^2+2^4+...+2^{2008}\right)$

$\Rightarrow3C=2^{2010}-1$

$\Rightarrow C=\frac{2^{2010}-1}{3}$