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a, \(5\sqrt{\left(-2\right)^4}=5\sqrt{2^4}=5.2^2=5.4=20\)
b, \(-4\sqrt{\left(-3\right)^6}=-4\sqrt{3^6}=-4.3^3=-4.27=-108\)
c,\(\sqrt{\sqrt{\left(-5\right)^8}}=\sqrt{\sqrt{5^8}}=\sqrt{5^4}=5^2=25\)
d ,\(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}\)
\(=2\sqrt{5^6}+3\sqrt{2^8}\)
=\(2.5^3+3.2^4=2.125+3.16=298\)
a) \(5\sqrt{\left(-2\right)^4}\) \(=5\left|\left(-2\right)^2\right|=5.4=20\)
b) \(-4\sqrt{\left(-3\right)^6}=-4\left|\left(-3\right)^3\right|=-4.27=-108\)
c) \(\sqrt{\sqrt{\left(-5\right)^8}}=\left|\left(-5\right)^4\right|=5^4=625\)
d) \(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}\) \(=2\left|\left(-5\right)^3\right|+3\left|\left(-2\right)^4\right|\)
\(=-2.\left(-125\right)+3.16\)
\(= 250 + 48 = 298\)
a) \(5\sqrt{\left(-2\right)^4}=5\sqrt{\left(2^2\right)^2}=5\left|4\right|=5.4=20\)
b)\(-4\sqrt{\left(-3\right)^6}=-4\sqrt{\left(3^3\right)^2}=-4\left|27\right|=-4.27=-108\)
c) \(\sqrt{\sqrt{\left(-5\right)^8}}=\sqrt{\sqrt{\left(5^4\right)^2}}=\sqrt{\left(5^2\right)^2}=25\)
d)
1. \(=\sqrt{\left(\sqrt{\frac{7}{2}}+\sqrt{\frac{3}{2}}\right)^2}+\sqrt{\left(\sqrt{\frac{7}{2}}-\sqrt{\frac{3}{2}}\right)^2}-2\sqrt{4\sqrt{7}}=\frac{7}{2}+\frac{3}{2}+\frac{7}{2}-\frac{3}{2}-2\sqrt{4\sqrt{7}}\)
\(=7-2\sqrt{4\sqrt{7}}\)
cho hỏi tại sao có số \(\frac{7}{2};\frac{3}{2}\)zậy chỉ với
\(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}\)
\(=2.5^3+3.2^4\)
\(=2.125+3.16\)
\(=298\)
a) \(5\sqrt{\left(-2\right)^4}=5\sqrt{\left(\left(-2\right)^2\right)^2}\) = \(5\left|\left(-2\right)^2\right|=5.4=20\)
b) \(-4\sqrt{\left(-3\right)^6}=-4\sqrt{\left(\left(-3\right)^3\right)^2}=-4\left|\left(-3\right)^3\right|\) = -4.27 = -108
\(c,2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}\) = \(2\sqrt{\left(\left(-5\right)^3\right)^2}+3\sqrt{\left(\left(-2\right)^4\right)^2}=2\left|\left(-5\right)^3\right|+3\left|\left(-2\right)^4\right|=2.125+3.16=298\)
a) \(5\sqrt{\left(-2\right)^4}=5\sqrt{\left(\left(-2\right)^2\right)^2}=5\sqrt{4^2}=5\left|4\right|=5.4=20\)
b) \(-4\sqrt{\left(-3\right)^6}=-4\sqrt{\left(\left(-3\right)^3\right)^2}=-4\sqrt{\left(-27\right)^2}=-4\left|-27\right|=-4.27=-108\)
c) \(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}=2\sqrt{\left(\left(-5\right)^3\right)^2}+3\sqrt{\left(\left(-2\right)^4\right)^2}\)
\(=2\sqrt{\left(-125\right)^2}+3\sqrt{16^2}=2\left|-125\right|+3\left|16\right|=2.125+3.16=250+48=298\)
\(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}.\)
\(=2\sqrt{\left(\left(-5\right)^3\right)^2}+3\sqrt{\left(\left(-2\right)^4\right)^2}\)
\(=2\cdot\left(-5\right)^3+3\cdot\left(-2\right)^4\)
\(=2\cdot125+3\cdot16=250+48=298\)
\(\Rightarrow2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}=298\)
\(2\sqrt{\left(-5\right)^6}+3\sqrt{\left(-2\right)^8}\)
\(=2\times125+3\times16\)
\(=250+48\)
\(=298\)