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b: \(=\dfrac{3}{7}\cdot\dfrac{5}{7}\cdot\dfrac{6}{7}=\dfrac{90}{343}\)
c: \(=\dfrac{4}{9}\cdot\dfrac{5}{9}\cdot\dfrac{3}{7}=\dfrac{20}{189}\)
d: \(=\dfrac{1}{3}\cdot\dfrac{5}{12}\cdot\dfrac{5}{12}=\dfrac{25}{432}\)
a: 78/42-4/7=13/7-4/7=9/7
100/110-56/88=10/11-7/11=3/11
75/35-11/7+21/49=15/7-11/7+3/7=7/7=1
99/72-15/40-1212/1616=11/8-3/8-3/4=1-3/4=1/4
Bài 1:
18/27=2/3
35/25=7/5
54/72=3/4
78/66=13/11
92/100=23/25
75/125=3/5
126/165=42/55
150/300=1/2
1717/1515=17/15
\(\frac{55}{66}-\frac{14}{21}=\frac{5}{6}-\frac{2}{3}=\frac{5}{6}-\frac{4}{6}=\frac{1}{6}\)
\(\frac{15}{25}+\frac{10}{20}=\frac{3}{5}+\frac{1}{2}=\frac{6}{10}+\frac{5}{10}=\frac{11}{10}\)
a. \(\frac{22}{55}\)+ \(\frac{25}{125}\)+ \(\frac{1020}{5100}\)
= \(\frac{2}{5}\)+ \(\frac{1}{5}\)+ \(\frac{1}{5}\)
= \(\frac{4}{5}\)
B. \(\frac{22}{77}\)+ \(\frac{56}{98}\)+ \(\frac{25}{105}\)
= \(\frac{2}{7}\)+ \(\frac{4}{7}\)+ \(\frac{5}{21}\)
= \(\frac{6}{7}\)+ \(\frac{5}{21}\)
= \(\frac{23}{21}\)
\(a.\dfrac{5}{10}=\dfrac{1}{2}=\dfrac{1\times3}{2\times3}=\dfrac{3}{6}\)
\(\dfrac{25}{75}=\dfrac{1}{3}=\dfrac{1\times2}{3\times2}=\dfrac{2}{6}\)
\(b.\dfrac{42}{56}=\dfrac{3}{4}=\dfrac{3\times2}{4\times2}=\dfrac{6}{8}\)
\(\dfrac{18}{48}=\dfrac{3}{8}\)
\(c.\dfrac{27}{81}=\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12}\)
\(\dfrac{57}{76}=\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)
\(\dfrac{35}{84}=\dfrac{5}{12}\)
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= 2/5 + 1/5 + 1/5
= 4/5
b. = 2/7 + 4/7 + 5/21
= 6/21 + 12/21 + 5/21
= 23/21
HT
a: \(\dfrac{75}{90}+\dfrac{26}{24}=\dfrac{5}{6}+\dfrac{13}{12}=\dfrac{10}{12}+\dfrac{13}{12}=\dfrac{23}{12}\)
b: \(\dfrac{42}{49}-\dfrac{38}{56}=\dfrac{6}{7}-\dfrac{19}{28}=\dfrac{24}{28}-\dfrac{19}{28}=\dfrac{5}{28}\)
c: \(\dfrac{51}{72}+\dfrac{55}{66}=\dfrac{17}{24}+\dfrac{5}{6}=\dfrac{17}{24}+\dfrac{20}{24}=\dfrac{37}{24}\)
d: \(\dfrac{1313}{1515}-\dfrac{20}{25}=\dfrac{13}{15}-\dfrac{4}{5}=\dfrac{13}{15}-\dfrac{12}{15}=\dfrac{1}{15}\)
\(\dfrac{5}{6}+\dfrac{13}{12}=\dfrac{10}{12}+\dfrac{13}{12}=\dfrac{23}{12}\)
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