Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a)\(\frac{-315}{540}\)=\(\frac{7}{12}\)
b)\(\frac{25.13}{26.35}\)=\(\frac{5}{14}\)
c)\(\frac{6.9-2.17}{63.3-119}\)=\(\frac{4}{7}\)
d)\(\frac{2929-101}{2.1919+404}\)=\(\frac{2}{3}\)
bài 1
a, 1/4giowf b,5/3 giờ
bài 3
-6/17=-6/17 -25/75=-1/3 42/-98=24/-49 -12/27=-4/9
bài 2 dài lắm bạn ơi ,mình chỉ giúp đc vậy thôi
Ta có:
\(\begin{array}{l}\frac{{24}}{{108}} = \frac{{24:12}}{{108:12}} = \frac{2}{9};\\\frac{{80}}{{32}} = \frac{{80:16}}{{32:16}} = \frac{5}{2}\end{array}\)
Trả lời:
a, \(\frac{6\times9-2\times17}{63\times3-119}=\frac{2.3\times9-2\times17}{7.9\times3-7.17}\)
\(=\frac{2\times\left(3\times9-17\right)}{7\times\left(3\times9-17\right)}\)
\(=\frac{2}{7}\)
b, \(\frac{3\times13-13\times18}{15\times40-80}=\frac{13\times\left(3-18\right)}{40\times\left(15-2\right)}\)
\(=\frac{13\times-15}{40\times13}\)
\(=\frac{-3}{8}\)
c, \(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}=\frac{-1997.1996+1}{\left(1-1996\right).\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{-1997-1996.\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{-1996.\left(-1997\right)-1}\)
\(=\frac{-1997.1996+1}{-\left[1996.\left(-1997\right)+1\right]}\)
\(=-1\)
d, \(\frac{3.7.13.37.39-10101}{505050-70707}=\frac{10101.39-10101}{50.10101-7.10101}\)
\(=\frac{10101.\left(39-1\right)}{10101.\left(50-7\right)}\)
\(=\frac{10101.38}{10101.43}\)
\(=\frac{38}{43}\)
Bài giải
a) Ta có : \(\frac{4545+101}{6969-303}=\frac{45.101+101}{69.101-101.3}=\frac{101.\left(45+1\right)}{101.\left(69-3\right)}=\frac{101.46}{101.66}=\frac{23}{33}\)
b) Ta có : \(\frac{2929-101}{2.1919+404}=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(19.2+4\right)}=\frac{28}{42}=\frac{2}{3}\)
a)\(\frac{4545+101}{6969-303}\)= \(\frac{\left(4545:45\right)+101}{\left(6969:69\right)-303}\)= \(\frac{101+101}{101-303}\)=\(\frac{202}{-202}\)=-1
b)\(\frac{2929-101}{2.1919+404}\)= \(\frac{2929-101}{3838+404}\)=\(\frac{\left(2929:29\right)-101}{\left(3838:38\right)+404}\)=\(\frac{101-101}{101+404}\)=\(\frac{0}{505}\)=0
học tốt
B = \(\frac{2015+2016+2017}{2016+2017+2018}=\frac{2016.3}{2017.3}=\frac{2016}{2017}\left(1\right)\)
Mà A = \(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}.\left(2\right)\)
Từ \(\left(1\right)\)và \(\left(2\right)\)=> A > B.
Vậy A > B .
Bạn Dont look at me
Bạn nên làm theo bạn ấy
Bạn k đúng cho bạn ấy. Bởi vì bạn ấy làm đúng
Theo mk là vậy
\(\text{Ta có :}\)\(-\frac{4.5+4.11}{8.7-4.3}=\frac{-4\left(5+11\right)}{4\left(2.7-3\right)}=\frac{-16}{24}=\frac{-4}{6}\)
\(\frac{-15.8+10.7}{5.6+20.3}=\frac{-5\left(3.8-2.7\right)}{5.\left(6+2.3\right)}=\frac{-10}{12}=\frac{-5}{6}\)
\(\text{Vì:}\)\(-\frac{4}{6}>\frac{-5}{6}\left(-4>-5\right)\)
\(\text{Nên :}\)\(-\frac{4.5+4.11}{8.7-4.3}>\)\(\frac{-15.8+10.7}{5.6+20.3}\)
\(-\frac{4.5+4.11}{8.7-4.3}=-\frac{4.\left(5+11\right)}{4.\left(14-3\right)}=-\frac{4.16}{4.11}=\frac{-16}{11}\)
\(\frac{-15.8+10.7}{5.6+20.3}=\frac{\left(-5\right).3.8+5.2.7}{5.2.3+2.2.5.3}=\frac{5.\left(-3.8+2.7\right)}{5.2.3.\left(1+2\right)}\)
\(=\frac{5.\left(-10\right)}{5.2.3.3}=\frac{-5}{9}\)
\(\frac{-5}{9}>\frac{-16}{11}\)
\(a.\frac{-12121212}{-30303030}=\frac{12121212}{30303030}=\frac{12121212:1010101}{30303030:1010101}=\frac{12}{30}=\)\(\frac{2}{5}\)
\(b.\frac{13.34-13.15}{19.29+19.10}=\frac{13.\left(34-15\right)}{19.\left(29+10\right)}=\frac{13.19}{19.39}=\frac{1}{3}\)
\(c.\frac{45.26-26.24}{21.91-21.13}=\frac{26.\left(45-24\right)}{21.\left(91-13\right)}=\frac{26.21}{21.78}=\frac{1}{3}\)
\(d.\frac{47.5}{-35.33-35.14}=\frac{47.5}{-35.\left(33+14\right)}=\frac{47.5}{-35.47}=\frac{-1}{7}\)
\(e.\frac{-15.34-15.46}{80}\frac{-15.\left(34+46\right)}{80}=\frac{-15.80}{80}=-15\)