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a) Ta có: \(\dfrac{11\cdot4-11}{2-13}\)
\(=\dfrac{11\left(4-1\right)}{-11}=\dfrac{4-1}{-1}=-3\)
b) Ta có: \(\dfrac{9\cdot6-9\cdot2}{18}\)
\(=\dfrac{9\cdot\left(6-2\right)}{18}\)
\(=\dfrac{4}{2}=2\)
c) Ta có: \(\dfrac{13\cdot2-13\cdot3}{1-14}\)
\(=\dfrac{13\cdot\left(2-3\right)}{-13}\)
=1
a) Ta có: \(\dfrac{11\cdot4-11}{2-13}\)
\(=\dfrac{11\cdot\left(4-1\right)}{-11}\)
\(=\dfrac{33}{-11}=-3\)
b) Ta có: \(\dfrac{9\cdot6-9\cdot2}{18}\)
\(=\dfrac{9\cdot\left(6-2\right)}{18}\)
\(=\dfrac{36}{18}=2\)
c) Ta có: \(\dfrac{13\cdot2-13\cdot3}{1-14}\)
\(=13\cdot\dfrac{\left(2-3\right)}{-13}\)
=1
a) 9.6 − 9.3 18 = 9. 6 − 3 18 = 9.3 2.9 = 3 2
b) 49 + 7.49 49 = 49. 1 + 7 49 = 8
\(-\frac{5}{10}=-\frac{1}{2}\)
\(\frac{18}{33}=\frac{6}{11}\)
\(\frac{19}{57}\)
\(\frac{-36}{-12}=\frac{3}{2}\)
\(=\dfrac{2^{19}\cdot3^9+2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}=\dfrac{2^{18}\cdot3^9\cdot\left(2+5\right)}{2^{19}\cdot3^9\cdot7}=\dfrac{1}{2}\)
a: \(=\dfrac{13\cdot\left(9-2\right)}{13}=7\)
b: \(=\dfrac{14\left(3-8\right)}{7\left(1+3\cdot3\right)}=2\cdot\dfrac{-5}{10}=-1\)
c: \(=\dfrac{54-72}{36}=\dfrac{-18}{36}=-\dfrac{1}{2}\)
d: \(=\dfrac{5^3}{10^2\cdot5}=\dfrac{5^2}{100}=\dfrac{1}{4}\)
\(=\dfrac{9\cdot4}{-18}=\dfrac{-36}{18}=-2\)