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a: \(=\dfrac{x-\sqrt{x}-x-2\sqrt{x}-1-2\sqrt{x}-4}{x-1}\)
\(=\dfrac{-5\sqrt{x}-5}{x-1}=\dfrac{-5}{\sqrt{x}-1}\)
b: \(=\dfrac{5x+10\sqrt{x}+\left(\sqrt{x}-3\right)\left(\sqrt{x}-2\right)-6x}{x-4}\)
\(=\dfrac{-x+10\sqrt{x}+x-5\sqrt{x}+6}{x-4}\)
\(=\dfrac{5\sqrt{x}+6}{x-4}\)
Bài 8:
a: Ta có: \(E=\left(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}\right):\left(\dfrac{1}{x+1}+\dfrac{x}{x-1}+\dfrac{2}{x^2-1}\right)\)
\(=\dfrac{x^2+2x+1-x^2+2x-1}{\left(x-1\right)\left(x+1\right)}:\dfrac{x-1+x^2+x+2}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{4x}{x^2+2x+1}\)
b: Thay x=3 vào E, ta được:
\(E=\dfrac{4\cdot3}{\left(3+1\right)^2}=\dfrac{12}{4^2}=\dfrac{3}{4}\)
Thay x=-3 vào E, ta được:
\(E=\dfrac{4\cdot\left(-3\right)}{\left(-3+1\right)^2}=\dfrac{-12}{4}=-3\)
\(P=\dfrac{2x+2+x+\sqrt{x}+1-x+\sqrt{x}-1}{\sqrt{x}}\)
\(=\dfrac{2x+2\sqrt{x}+2}{\sqrt{x}}\)
\(1,\sqrt{4\left(a-4\right)^2}\left(dkxd:a\ge4\right)\)
\(=\sqrt{4}.\sqrt{\left(a-4\right)^2}\)
\(=\sqrt{2^2}.\left|a-4\right|\)
\(=2\left(a-4\right)\)
\(=2a-8\)
\(2,\sqrt{9\left(b-5\right)^2}\left(dkxd:b< 5\right)\)
\(=\sqrt{9}.\sqrt{\left(b-5\right)^2}\)
\(=\sqrt{3^2}.\left|b-5\right|\)
\(=3\left(-b+5\right)\)
\(=-3b+15\)
\(\dfrac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\dfrac{6+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}\\ =\dfrac{\sqrt{3}\left(\sqrt{5}-\sqrt{4}\right)}{\sqrt{5}-\sqrt{4}}+\dfrac{\sqrt{2}.\sqrt{6}\left(\sqrt{3}+\sqrt{2}\right)}{\sqrt{3}+\sqrt{2}}\\ =\sqrt{3}+\sqrt{12}\\ =\sqrt{3}+\sqrt{2^2.3}\\ =\sqrt{3}+2\sqrt{3}\\ =3\sqrt{3}\)
\(\dfrac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\dfrac{6+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}\)
\(=\dfrac{\sqrt{3}\left(\sqrt{5}-\sqrt{4}\right)}{\sqrt{5}-2}+\dfrac{\sqrt{12}\left(\sqrt{3}+\sqrt{2}\right)}{\sqrt{3}+\sqrt{2}}\\ =\sqrt{3}+\sqrt{12}\\ =\sqrt{3}+2\sqrt{3}=3\sqrt{3}\)