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6 tháng 3 2018

\(A=\frac{10.11+50.55+70.77}{11.12+55.60+77.84}\)

\(=\frac{10.11+5.10.5.11+7.10.7.11}{11.12+11.5.12.5+11.7.12.7}\)

\(=\frac{10.11\left(1+25+49\right)}{11.12\left(1+25+49\right)}\)

\(=\frac{10.11}{11.12}=\frac{10}{12}=\frac{5}{6}\)

\(B=\frac{1\times3\times5\times7\times........\times49}{26\times27\times28\times...........\times50}\)

\(=\frac{\left(1\times3\times5\times7\times.........\times49\right).\left(2\times4\times6.........48\times50\right)}{\left(26\times27\times28\times.........\times50\right).\left(2\times4\times6\times...........\times48\times50\right)}\)

\(=\frac{1\times2\times3\times4\times..........\times50}{\left(26\times27\times28\times..............\times50\right)2^{25}\left(1\times2\times3\times4\times............\times25\right)}=\frac{1}{2^{25}}\)

\(C=\frac{1.2.6+2.4.12+4.8.24+7.14.42}{1.6.9+2.12.18+4.24.36+7.42.63}\)

\(=\frac{1.2.6\left(1+8+64+343\right)}{1.6.9\left(1+8+64+343\right)}\)

\(=\frac{1.2.6}{1.6.9}=\frac{2}{9}\)

6 tháng 3 2018

\(A=\frac{5}{6}\)

\(B=\frac{1}{33554432}\)

\(C=\frac{28}{117}\)

14 tháng 1 2016

bn ơi, cho mjk cách lm với 

21 tháng 10 2015

\(\frac{10.11+55.60+70.77}{11.12+55.60+77.84}=\frac{10.11+5.11.6.10+7.10.7.11}{11.12+5.11.5.12+7.11.7.12}=\frac{10.11+30.10.11+49.10.11}{11.12+25.11.12+49.11.12}=\frac{10.11\left(1+30+49\right)}{11.12\left(1+25+49\right)}=\frac{5.80}{6.75}=\frac{8}{9}\)

25 tháng 3 2017

\(\dfrac{10+x}{17+x}=\dfrac{10\cdot11+50\cdot55+70\cdot77}{11\cdot12+55\cdot66+77\cdot84}\)

\(\Leftrightarrow\dfrac{10+x}{17+x}=\dfrac{10\cdot11+5\cdot10\cdot111+7\cdot10\cdot11}{11\cdot12+5\cdot11\cdot12+7\cdot11\cdot12}\)

\(\Leftrightarrow\dfrac{10+x}{17+x}=\dfrac{10\cdot11\left(1+5+7\right)}{11\cdot12\left(1+5+7\right)}\)

\(\Leftrightarrow\dfrac{10+x}{17+x}=\dfrac{5}{6}\)

\(\Leftrightarrow6\left(10+x\right)=5\left(17+x\right)\)

\(\Leftrightarrow60+6x=85+5x\)

\(\Leftrightarrow6x-5x=85-60\)

\(\Leftrightarrow x=25\) (TM x\(\ne17\))

Vậy ...................................

18 tháng 6 2019

#)Giải :

a) \(A=\frac{4^5.9^4-2^6.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{1}{3}\)

\(a,A=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-1}{3}\)

Học tốt!!!!!!!!!!!!!

6 tháng 6 2015

A = \(\frac{7}{10.11}+\frac{7}{11.12}+\frac{7}{12.13}+...+\frac{7}{69.70}\)

=\(7\left(\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}+...+\frac{1}{69.70}\right)\)

=\(7\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)

=\(7\left(\frac{1}{10}-\frac{1}{70}\right)\)

=\(7.\frac{3}{35}\)

=\(\frac{3}{5}\)

B=\(\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)

=\(\frac{1}{2}\left(\frac{2}{25.27}+\frac{2}{27.29}+\frac{2}{29.31}+...+\frac{2}{73.75}\right)\)

=\(\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)

=\(\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)\)

=\(\frac{1}{2}.\frac{2}{75}\)

=\(\frac{1}{75}\)

6 tháng 6 2015

C : có ở bên dưới rồi, còn A và B thôi

18 tháng 2 2017

 a) \(\frac{9}{33-3}=\frac{1}{3}\)

b) \(\frac{7}{100+6\times100}=\frac{1}{100}\)

c) \(\frac{11\times22+33\times36+55\times60}{22\times24+66\times72+110\times120}=\frac{1}{4}\)

d) \(\frac{9^4\times27^5\times3^6\times4^4}{3^8\times81^4\times243\times8^2}=4\)

e) \(\frac{199919991999}{200020002000}=\frac{1999}{2000}\)

19 tháng 2 2017

Cảm ơn bạn ^.^