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a) 2x(x+3) – 3x2(x+2) + x(3x2 + 4x – 6)
= (2x . x + 2x . 3) – (3x2 . x + 3x2 . 2) + (x . 3x2 + x . 4x – x . 6)
= 2x2 + 6x – (3x3 + 6x2) + (3x3 + 4x2 - 6x)
= 2x2 + 6x – 3x3 – 6x2 + 3x3 + 4x2 - 6x
= (– 3x3 + 3x3 ) + (2x2 - 6x2 + 4x2 ) + (6x – 6x)
= 0 + 0 + 0
= 0
b) 3x(2x2 – x) – 2x2(3x+1) + 5(x2 – 1)
= [3x . 2x2 + 3x . (-x)] – (2x2 . 3x + 2x2 . 1) + [5x2 + 5 . (-1)]
= 6x3 – 3x2 – (6x3 +2x2) + 5x2 – 5
= 6x3 – 3x2 – 6x3 - 2x2 + 5x2 – 5
= (6x3 – 6x3 ) + (-3x2 – 2x2 + 5x2) – 5
= 0 + 0 – 5
= - 5
a) \(A=x^2-4x+1=\left(x-2\right)^2-3\ge-3\)
\(minA=-3\Leftrightarrow x=2\)
b) \(B=-x^2-8x+5=-\left(x+4\right)^2+21\le21\)
\(maxB=21\Leftrightarrow x=-4\)
c) \(C=2x^2-8x+19=2\left(x-2\right)^2+11\ge11\)
\(minC=11\Leftrightarrow x=2\)
d) \(D=-3x^2-6x+1=-3\left(x+1\right)^2+4\le4\)
\(maxD=4\Leftrightarrow x=-1\)
\(a\\ -5x^2+3x.\left(x+2\right)=-5x^2+3x^2+6x=-2x^2+6x\\ b\\ -2x.\left(1-x^2\right)-2x^3=-2x+2x^3-2x^3=-2x\\ c\\ 4x.\left(x-1\right)-4.\left(x^2+2x-1\right)\\ =4x^2-4x-4x^2-8x+4=-12x+4\)
\(d\\ 6x^3-2x^2.\left(-x^2-3x\right)=6x^3+2x^4+6x^3=2x^4+12x^3\\ e\\ 3x.\left(x-1\right)-\left(1+2x\right).5x\\ =3x^2-3x-5x-10x^2=-7x^2-8x\\ f\\ -5x^2-\left(x-6\right).\left(-2x^2\right)=-5x^2+2x^3-12x^2=2x^3-17x^2\)
\(a,N\left(x\right)=x^2+3x^4-2x-x^2+2x^3=3x^4+2x^3+\left(x^2-x^2\right)-2x\\ =3x^4+2x^3-2x\\ P\left(x\right)=-8+5x-6x^3-4x+6=-6x^3+\left(5x-4x\right)+\left(-8+6\right)\\ =-6x^3+x-2\)
Bậc của N(x) là 4
Bậc của P(x) là 3
\(b,P\left(x\right)+N\left(x\right)=3x^4+2x^3-2x-6x^3+x-2\\ =3x^4+\left(2x^3-6x^3\right)+\left(-2x+x\right)-2\\ =3x^4-4x^3-x-2\)
\(c,B\left(x\right)=-2x^2\left(x^3-2x+5x^2-1\right)\\ =\left(-2x^2\right).x^3+\left(-2x^2\right).\left(-2x\right)+\left(-2x^2\right).5x^2+\left(-2x^2\right).\left(-1\right)\\ =-2x^5+4x^3-10x^4+2x^2\\ =-2x^5-10x^4+4x^3+2x^2\)
(4x3 + 2x2 − 1) − (4x3 − x2 + 1)
= 4x3 + 2x2 – 1 – 4x3 + x2 – 1
= (4x3 – 4x3) + (2x2 + x2 ) – (1+ 1)
= 3x2 – 2
Chọn đáp án C
`#Namnam041005`
`a)`
`A(x) =`\(x^5+ x^3- 4x - x^5 + 3x - x^2 + 7\)
`= (x^5 - x^5) + x^3 - x^2 + (-4x + 3x) + 7`
`= x^3 - x^2 - x + 7`
`B(x) = `\(3x^2 - x^5 + 5x - 2x^2 - 9\)
`= (3x^2 - 2x^2) - x^5 + 5x - 9`
`= -x^5 + x^2 + 5x - 9`
`b)`
`A(x)``= x^3 - x^2 - x + 7`
Bậc của đa thức: `3`
Hệ số cao nhất: `1`
Hệ số tự do: `7`
`c)`
`A(x) + B(x) = x^3 - x^2 - x + 7 -x^5 + x^2 + 5x - 9`
`= -x^5 + x^3 + (-x^2 + x^2) + (-x+5x) + (7-9)`
`= -x^5 + x^3 + 4x - 2`
`A(x) - B(x) = x^3 - x^2 - x + 7 - (-x^5 + x^2 + 5x - 9)`
`= x^3 - x^2 - x + 7 +x^5 - x^2 - 5x + 9`
`= x^5 + x^3 + (-x^2 - x^2) + (-x-5x) + (7+9)`
`= x^5 + x^3 - 2x^2 - 6x + 16`
___
`A(x) + B(x) = -x^5 + x^3 + 4x - 2=0`
Bạn xem lại đề
`d)`
`H(x) - B(x) = x^3 + x^2 - x + 1`
`=> H(x) = (x^3 + x^2 - x + 1) + B(x)`
`=> H(x) = x^3 + x^2 - x + 1 -x^5 + x^2 + 5x - 9`
`= -x^5 + x^3 + (x^2 + x^2) + (-x+5x) + (1 - 9)`
`= -x^5 + x^3 + 2x^2 + 4x - 8`
a: A(x)=x^5-x^5+x^3-x^2-4x+3x+7
=x^3-x^2-x+7
B(x)=-x^5+3x^2-2x^2+5x-9
=-x^5+x^2+5x-9
b: Bậc: 3
Hệ số cao nhất: 1
hệ số tự do: 7
c: A(x)+B(x)
=x^3-x^2-x+7-x^5+x^2+5x-9
=-x^5+x^3+4x-2
A(x)-B(x)
=x^3-x^2-x+7+x^5-x^2-5x+9
=x^5+x^3-2x^2-6x+16
d: H(x)=x^3+x^2-x+1+B(x)
=x^3+x^2-x+1-x^5+x^2+5x-9
=-x^5+x^3+2x^2+4x-8