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.5.7.11.13.37-10101/1212120+40404
=3.5.7.11.13.37-10101/1212120.1/10+40404 (vì 1/1212120=1/121212.1/10)
= 3.37.7.11.13.5-101010/121212.1/100+40404
=111.1001.5-5/6.1/100+40404
=151515.5-250/3
=595959-250/3
=1787876/3
Ta có:
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{\left(3.7.11.13.37\right).5-10101.1}{120.10101+4.10101}\)
\(=\frac{10101.\left(5-1\right)}{10101.\left(120+4\right)}\)
\(=\frac{4}{124}=\frac{1}{31}\)
Sai rồi:
A = 5.11.(3.7.13.37) - 10101/(10101.120 + 10101.4)
= (5.11.10101 - 10101)/(10101.120+10101.4)
= 10101(5.11-1)/10101(120+4)
= 27/62.
A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62
đúng nhé
A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{15015.37-273.37}{32760.37+1093.37}\)
\(=\frac{14742.37}{33853.37}\)
\(=\frac{14742}{33853}\)
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(A=\frac{\left(3.7.13.17\right).\left(5.11\right)-10101}{120.10101+4.10101}\)
\(A=\frac{10101.55-10101.1}{120.10101+4.10101}\)
\(A=\frac{10101.\left(55-1\right)}{10101.\left(120+4\right)}\)
\(A=\frac{10101.54}{10101.124}\)
\(A=\frac{54}{124}\)
\(A=\frac{27}{62}\)
- chúc bn hok tốt
#Hạ
\(\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{3.5.7.11.13.37-3.7.13.37}{40404.30+40404.1}\)
\(=\frac{3.7.13.37.\left(5.11-1\right)}{40404.\left(30+1\right)}\)
\(=\frac{3.7.13.37.54}{40404.31}\)
\(=\frac{3.7.13.37.54}{3.7.13.37.31.4}\)
\(=\frac{54}{31.4}=\frac{27}{62}\)
Ta có : \(\frac{3\cdot5\cdot7\cdot11\cdot13\cdot37-10101}{1212120+40404}\)
\(=\frac{(3\cdot7\cdot11\cdot13\cdot37)\cdot5-10101\cdot1}{120\cdot10101+4\cdot10101}\)
\(=\frac{10101\cdot(5-1)}{10101\cdot(120+4)}=\frac{4}{124}=\frac{1}{31}\)
~Chúc bạn học tốt~
Thank you boy