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\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{15}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}\left(3^5+5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)
cho mk sửa lại xíu:
\(\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}=\frac{2.6}{3.5}=\frac{12}{15}=\frac{4}{5}\)
mk sai xíu. hihi, học tốt nhé !
A=(2^2)^6.(3^2)^5+2^9.3^9.2^3.5.3/2^12.3^10+2^11.3^11
=2^12.3^10+2^12.3^10.5/2^12.3^10+2^11.3.3^10
=2^12.3^10.(1+5)/2^11.3^10.(2+3)
=2^11.2.6/2^11.5
=12/5
\(10.\frac{\left(2^2\right)^6.\left(3^3\right)^5+\left(2.3\right)^9.\left(2^3.3.5\right)}{\left(2^4\right)^3.3^{12}-\left(2.3\right)^{11}}\)
\(=10.\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=10.\frac{2^{12}.3^{10}\left(3^5+1.5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)
\(=10\frac{2\left(3^5+5\right)}{3.5}\)
\(=10.\frac{496}{15}\)
\(=\frac{992}{3}\)
Study well
10.\(\frac{241864704+1209323520}{2176782336-6^{11}}\)
=10.\(\frac{362797224}{1813985280}\)
=2,000000926
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