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a/\(\left(2x+1\right)^2-\left(2x+3\right)\left(2x-3\right).\)
\(=\left(4x^2+4x+1\right)-\left(4x^2-9\right)\)
\(=4x^2+4x+1-4x^2+9\)
\(=4x+10\)
b/\(4\left(x-1\right)\left(x+3\right)+5\left(2x+1\right)^2-2\left(5-3x\right)^2\)
\(=4\left(x^2+3x-x-3\right)+5\left(4x^2+4x+1\right)-2\left(25-30x+9x^2\right)\)
\(=4\left(x^2+2x-3\right)+5\left(4x^2+4x+1\right)-2\left(25-30x+9x^2\right)\)
\(=4x^2+8x-12+20x^2+20x+5-50+60x-18x^2\)
\(=6x^2+88x-57\)
mik tính toán cẩu thả lắm ạ có j sai ib ạ. Cảm ơn :3
`Answer:`
`a)`
`A=5(x+1)^2-3(x-3)^2-4(x^2-4)`
`=>A=5(x^2+2x+1)-3(x^2-6x+9)-4x^2+16`
`=>A=5x^2+10x+5-3x^2+18x-27-4x^2+16`
`=>A=(5x^2-3x^2-4x^2)+(10x+18x)+(5-27+16)`
`=>A=-2x^2+28x-6`
`b)`
`B=5(x+1)^2-3(x-3)^2-4(x+2)(x-2)`
`=2x(3x+5)-3(3x+5)-2x(x^2-4x+4)-[(2x)^2-3^2]`
`=6x^2+10x-9x-15-2x^3+8x^2-8x-4x^2+9`
`=(6x^2-4x^2+8x^2)-2x^3+(10x-9x-8x)+(-15+9)`
Thay `x=-7` vào ta được:
`B=10(-7)^2-2(-7)^3-7(-7)-6`
`=>B=10.49-2(-343)+49-6`
`=>B=490+686+49-6`
`=>B=1219`
ta có: a) (x+2)(x2-2x+4)-(18+x3)
=(x3+4)-(18+x3)
=x3+8-18-x3
=8-18
=-10
b)(x-3)(x+3)-(x+5)(x-1)=(x2-9)-(x2-x+5x-5)
=(x2-9)-(x2+4x-5)
=x2-9-x2-4x+5
=-9-4x+5
=-4-4x
=4(-1-x)
\(4\left(x-1\right)\left(x+3\right)+5\left(2x+1\right)^2-2\left(5-3x\right)^2\)
\(=\left(4x-1\right)\left(x+3\right)+5\left[\left(2x\right)^2+2.2x+1\right]-2\left[5^2-2.5.3x+\left(3x\right)^2\right]\)
\(=4x^2+12x-4x-12+20x^2+20x+5-50+60x-18x^2\)
\(=6x^2+88x-57\)
a) (2x+1)^2+2(4x^2-2)+(2x-1)^2=4x2+4x+1+8x2-4+4x2-4x+1=16x2-2
\(B=5\cdot\left(2x-1\right)^2+4\cdot\left(x-1\right)\cdot\left(x+3\right)-2\cdot\left(5\cdot3x\right)\)
\(=5\left(4x^2-4x+1\right)+\left(4x-4\right)\cdot\left(x+3\right)-2\cdot15x\)
\(=20x^2-20x+5+4x^2+12x-4x-12-2\cdot15x\)
\(=20x^2-20x+5+4x^2+12x-4x+12-30x\)
\(=24x^2-42x-7\)
(B=5left(2x-1 ight)^2+4left(x-1 ight)left(x+3 ight)-2left(5.3x ight)=5left(4x^2-4x+1 ight)+4left(x^2-4x+3 ight)-30x=20x^2-20x+5+4x^2-16x+12-30x=24x^2-66x+17)