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24 tháng 7 2016

A=có cần đọc cách làm ko bạn

24 tháng 7 2016

A, B, C,... là tên của bài bạn nha

VD: A, 15+x=15

      B, 16+14+14+14

12 tháng 2 2018

\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{8}{25-3}=\frac{8}{22}=\frac{4}{11}\)

\(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}=\frac{5-9}{14}=\frac{-4}{14}=\frac{-2}{7}\)

\(\frac{-2}{7}=\frac{-22}{77}\)

\(\frac{4}{11}=\frac{28}{77}\)

27 tháng 7 2018

= 28/77 

      

17 tháng 2 2016

a. \(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.3^2.2.3^2}{2^2.3^2.5}=\frac{2.9}{5}=\frac{18}{5}\)

b. \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.5^2.7.11.2.11}{2^3.5^2.7.11.5.7}=\frac{2.11}{5.7}=\frac{22}{35}\)

25 tháng 7 2016

A) \(\frac{8^{15}.3^{17}}{4^{23}.9^9}=\frac{2^{45}.3^{17}}{2^{46}.3^{18}}=\frac{2^{45}.3^{17}}{2^{45}.3^{17}.\left(2.3\right)}=\frac{1}{6}\)

B)\(\frac{28^{15}.3^{17}}{84^{16}}=\frac{\left(2^2.7\right)^{15}.3^{17}}{\left(2^2.3.7\right)^{16}}=\frac{2^{30}.7^{15}.3^{17}}{2^{32}.3^{16}.7^{16}}=\frac{2^{30}.7^{15}.3^{16}.3}{2^{30}.7^{15}.3^{16}.\left(2^2.7\right)}=\frac{3}{28}\)

C) \(\frac{3^{10}+6^2}{5.3^8+20}=\frac{3^{10}+2^2.3^2}{5.3^8+2^2.5}=\frac{3^2.\left(3^8+2^2\right)}{5.\left(3^8+2^2\right)}=\frac{9}{5}\)

D) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{2^7.3^5.3}{2^7.3^5.2^4}=\frac{3}{16}\)

F) \(\frac{5^4.20^4}{25^4.4^5}=\frac{5^4.\left(2^2.5\right)^4}{\left(5^2\right)^4.\left(2^2\right)^5}=\frac{5^4.2^8.5^4}{5^8.2^{10}}=\frac{5^8.2^8}{5^8.2^8.2^2}=\frac{1}{4}\)

G) \(\frac{5^5+25^2+5^2}{-151}=\frac{5^5+5^4+5^2}{-151}=\frac{5^2.\left(5^3+5^2+1\right)}{-151}=\frac{25.151}{-151}=-25\)

25 tháng 7 2016

A,\(\frac{8^{15}.3^{17}}{4^{23}.9^9}=\frac{\left(2^3\right)^{15}.3^{17}}{\left(2^2\right)^{23}.\left(3^2\right)^9}=\frac{2^{45}.3^{17}}{2^{46}.3^{18}}=\frac{1.1}{2.3}=\frac{1}{6}\)

B,\(\frac{28^{15}.3^{17}}{84^{16}}=\frac{28^{15}.3^{17}}{28^{16}.3^{16}}=\frac{1.3}{28.1}=\frac{3}{28}\)

C,\(\frac{3^{10}+6^2}{5.3^8+20}=\frac{3^{10}+3^2.2^2}{5.3^8+5.2^2}=\frac{3^2.\left(3^8+2^2\right)}{5.\left(3^8+2^2\right)}=\frac{3^2}{5}=\frac{9}{5}\)

D,\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)

F,\(\frac{5^4.20^4}{25^4.4^5}=\frac{5^4.5^4.4^4}{\left(5^2\right)^4.4^5}=\frac{5^8.4^9}{5^8.4^5}=\frac{1}{4}\)

G,xin lỗi mik ko lm đc câu này.

Nhưng mik cũng đã cố gắng làm giúp bn mấy câu trên. k cho mik nha.

24 tháng 7 2017

\(A=2^0+2^1+2^2\)\(+2^3+...+\)\(2^{50}\)

\(2A=2+2^2+2^3+...+2^{51}\)

\(2A-A=A=2^{51}-2^0\)

\(B=5+5^2+5^3+...+5^{99}+5^{100}\)

\(5B=5^2+5^3+5^4+...+5^{100}+5^{101}\)

\(5B-B=4B=5^{101}-5\)

\(B=\frac{5^{101}-5}{4}\)

\(C=3-3^2+3^3-3^4+...+\)\(3^{2007}-3^{2008}+3^{2009}-3^{2010}\)

\(3C=3^2-3^3+3^4-3^5+...-3^{2008}+3^{2009}-3^{2010}+3^{2011}\)

\(3C+C=4C=3^{2011}+3\)

\(C=\frac{3^{2011}+3}{4}\)

\(S_{100}=5+5\times9+5\times9^2+5\times9^3+...+5\times9^{99}\)

\(S_{100}=5\times\left(1+9+9^2+9^3+...+9^{99}\right)\)

\(9S_{100}=5\times\left(9+9^2+9^3+...+9^{99}+9^{100}\right)\)

\(9S_{100}-S_{100}=8S_{100}=5\times\left(9^{100}-1\right)\)

\(S_{100}=\frac{5\times\left(9^{100}-1\right)}{8}\)

24 tháng 10 2023

A=20+21+22+23+...++23+...+250250

2�=2+22+23+...+2512A=2+22+23+...+251

2�−�=�=251−202AA=A=25120

�=5+52+53+...+599+5100B=5+52+53+...+599+5100

5�=52+53+54+...+5100+51015B=52+53+54+...+5100+5101

5�−�=4�=5101−55BB=4B=51015

�=5101−54B=451015

�=3−32+33−34+...+C=332+3334+...+32007−32008+32009−320103200732008+3200932010

3�=32−33+34−35+...−32008+32009−32010+320113C=3233+3435+...32008+3200932010+32011

3�+�=4�=32011+33C+C=4C=32011+3

�=32011+34C=432011+3

�100=5+5×9+5×92+5×93+...+5×999S100=5+5×9+5×92+5×93+...+5×999

�100=5×(1+9+92+93+...+999)S100=5×(1+9+92+93+...+999)

9�100=5×(9+92+93+...+999+9100)9S100=5×(9+92+93+...+999+9100)

9�100−�100=8�100=5×(9100−1)9S100S100=8S100=5×(91001)

�100=5×(9100−1)8S100=85×(91001)

23 tháng 9 2017

1,

a, \(11.11.11=11^3\)

b,\(55.5.5.13.13=55.5^2.13^2\)

c, \(3^7.3^{10}.3^2=3^{\left(7+10+2\right)}=3^{19}\)

d, \(2^5.2^6.2^7.2.2.2=2^5.2^6.2^7.2^3\)

e, \(2^9:2^3.2^4=2^6.2^4=2^{10}\)

2,

\(4^9:8^5=8\)

\(32^{10}:8^5=4^{10}.8^{10}:8^5=4^{10}.8^5\)

\(9^{15}:27^{10}=9^{15}:9^{10}.3^{10}=9^5.3^{10}\)( tự tính)

3, 

Ta có:

\(7^{200}=7^{2.100}=\left(7^2\right)^{100}=49^{100}\)

\(2^{700}=2^{7.100}=\left(2^7\right)^{100}=128^{100}\)

Vì \(128^{100}>49^{100}\)nên \(2^{700}>7^{200}\)

5 tháng 3 2017

A/B=5.4^15.9^9-4.3^20.8^9/2^29.3618.6^19-7.2^29.27^6

=2^29.3618.(5.2-3^2)/2^28.3^18.(5.3-7.2)

=2.1/1

=2

vậy A:B=2

6 tháng 3 2017

bằng 2 đó bạn

7 tháng 8 2016

Ta có:

\(8^3:8^4=\left(2^3\right)^3:\left(2^3\right)^4\)

\(=2^9:2^{12}=2^{9-12}=2^{-3}\)

Hình như có gì sai sai đó

7 tháng 8 2016

83:84= 83-4=8-1=0,125