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\(\Rightarrow A+B+C+D=14346\)
\(\Rightarrow A=\frac{445,644}{2}=222,822\)
\(\Rightarrow C=369-\left(\frac{1}{2}:5\right)=369-\frac{1}{10}=368,9\)
\(\Rightarrow B=222,822:2+368,9=111,411+368,9=480,311\)
\(\Rightarrow D=14346-222,822-368,9-480,311=13273,967\)
Đề cảu bạn mình chả hiểu cái gì hết Đặng Quang Dũng
\(tíchnha\)
\(\left(a\right)\frac{34-x}{30}=\frac{5}{6}\)
\(\frac{34-x}{30}=\frac{25}{30}\)
34 - x = 25
x = 34 - 25 = 9
\(\left(b\right)\frac{x+13}{34}=\frac{12}{17}\)
\(\frac{x+13}{34}=\frac{24}{34}\)
x + 13 = 24
x = 24 - 13 = 11
\(\left(c\right)\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{56}{81}\)
\(4x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
Đặt \(A=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
Ta có : \(3A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(3A-A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}-\frac{1}{81}\)
\(2A=1-\frac{1}{81}=\frac{80}{81}\)
\(A=\frac{80}{81}\div2=\frac{40}{81}\)
\(\Rightarrow4x+\frac{40}{81}=\frac{56}{81}\)
\(4x=\frac{56}{81}-\frac{40}{81}\)
\(4x=\frac{16}{81}\)
\(x=\frac{16}{81}\div4=\frac{4}{81}\)
8,96 : X =2,03 -0,5
8,96 :X = 1,53
X = 8,96 -1,53
X = 7,43
1,2 .X = 0,54 - 0,06
1,2 .X = 0,48
X = 1,2 : 0,48
X = 2,5
\(\frac{17}{5}\)= 2\(\frac{7}{5}\); \(\frac{139}{12}\)= 10\(\frac{19}{12}\); \(\frac{150}{13}\)= 11\(\frac{7}{13}\)
NHỚ TK CHO MÌNH NHÉ
\(\frac{3}{34}+\frac{34}{34}.\frac{3}{4}=\frac{3}{34}+1.\frac{3}{4}=\frac{3}{34}+\frac{3}{4}=\frac{57}{68}\)
\(\frac{23}{3}.\frac{56}{6}+\frac{86}{78}=\frac{23}{3}.\frac{28}{3}+\frac{43}{39}=\frac{644}{9}+\frac{28}{3}=\frac{728}{9}\)
\(\frac{3}{45}:\frac{1}{4}=\frac{1}{15}.4=\frac{4}{15}\)
\(\frac{5}{34}-\frac{3}{6}=\frac{5}{34}-\frac{1}{2}=\frac{3}{4}\)
\(\frac{1}{31}+\frac{1}{32}+...........+\frac{1}{89}+\frac{1}{90}>\frac{5}{6}\)
a) MC: 20
\(\frac{3}{4}\)=\(\frac{3x5}{4x5}\)=\(\frac{15}{20}\)
\(\frac{2}{5}\)=\(\frac{2x4}{5x4}\)=\(\frac{8}{20}\)
b) MC: 36
\(\frac{5}{12}\)=\(\frac{5x3}{12x3}\)=\(\frac{15}{36}\)
\(\frac{11}{36}\)giữ nguyên
c) MC: 60
\(\frac{2}{3}\)=\(\frac{2x20}{3x20}\)=\(\frac{40}{60}\)
\(\frac{3}{4}\)=\(\frac{3x15}{4x15}\)=\(\frac{45}{60}\)
\(\frac{4}{5}\)=\(\frac{4x12}{5x12}\)=\(\frac{48}{60}\)
a ) Ta có :
\(\frac{3}{4}=\frac{3.5}{4.5}=\frac{15}{20}\)
\(\frac{2}{5}=\frac{2.4}{5.4}=\frac{8}{20}\)
Dấu \(.\)là dấu nhân
Ta có :
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+\frac{29}{30}+\frac{55}{56}+\frac{71}{72}+\frac{89}{90}\)
\(=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+...+\left(1-\frac{1}{72}\right)+\left(1-\frac{1}{90}\right)\)
\(=\left(1+1+1+1+1+1+1+1+1\right)-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{72}+\frac{1}{90}\right)\)
\(=1\times9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}+\frac{1}{9.10}\right)\)
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}\)
\(=\frac{90}{10}-\frac{9}{10}\)
\(=\frac{81}{10}\)
~ Ủng hộ nhé
helo anh Oops Channy
Oops channy giả mạo. Nhìn ảnh là bít. Nếu thật thì phải là ảnh Channy