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21 tháng 6 2018

Giải:

1) \(\left(x-6\right)\left(x^2+6x+36\right)-\left(x+4\right)^3=\left(x-2\right)^3+\left(x+5\right)\left(x^2-10x+25\right)-\left(2x^3+6x^2\right)\)

\(\Leftrightarrow x^3-216-\left(x^3+12x^2+48x+64\right)=x^3-6x^2+12x-8+x^3+125-2x^3-6x^2\)

\(\Leftrightarrow x^3-216-x^3-12x^2-48x-64=x^3-6x^2+12x-8+x^3+125-2x^3-6x^2\)

\(\Leftrightarrow-280-12x^2-48x=-12x^2+12x+117\)

\(\Leftrightarrow-280-48x-12x-117=0\)

\(\Leftrightarrow-397-60x=0\)

\(\Leftrightarrow-60x=397\)

\(\Leftrightarrow x=-\dfrac{397}{60}\)

Vậy ...

2) \(\left(2x+3\right)^3-\left(2x+5\right)\left(4x^2-10x+25\right)=\left(6x-1\right)^2-\left(x-2\right)\left(x^2+2x+4\right)+x^3\)

\(\Leftrightarrow8x^3+36x^2+54x+27-\left(8x^3+125\right)=36x^2-12x+1-\left(x^3-8\right)+x^3\)

\(\Leftrightarrow8x^3+36x^2+54x+27-8x^3-125=36x^2-12x+1-x^3+8+x^3\)

\(\Leftrightarrow54x-98=-12x+9\)

\(\Leftrightarrow54x+12x=9+98\)

\(\Leftrightarrow66x=107\)

\(\Leftrightarrow x=\dfrac{107}{66}\)

Vậy ...

3 tháng 9 2018

\(C=x^{14}-10x^{13}+10x^{12}-10x^{11}+...+10x^2-10x+10\)

\(=x^{14}-\left(x+1\right)x^{13}+\left(x+1\right)x^{12}-\left(x+1\right)x^{11}+..+\left(x+1\right)x^2-\left(x+1\right)x+x+1\)

\(=x^{14}-x^{14}-x^{13}+x^{13}+x^{12}-x^{12}-x^{11}+...+x^3+x^2-x^2-x+x+1\)

\(=1\)

27 tháng 11 2016

x^4+5x^2-5x^2-25+2x^3+10x

= x^2(x^2+5)-5(x^2+5)+2x(x^2+5)

=(x^2+5)(x^2-5+2x):(x^2+5)

= x^2-5+2x

21 tháng 4 2020

( x+ 2x3 + x - 25 ) : ( x2 +5) 

1: \(\Leftrightarrow5x^2+4x-1-2x^2+12x-18=3x^2+5x-2-x^2-8x-16+x^2-x\)

\(\Leftrightarrow3x^2+16x-19=3x^2-4x-18\)

=>20x=1

hay x=1/20

2: \(\Leftrightarrow5x^2-20x-41=x^2-10x+25+4x^2+4x+1-\left(x^2-2x\right)+\left(x-1\right)^2\)

\(\Leftrightarrow5x^2-20x-41=4x^2-4x+26+x^2-2x+1\)

\(\Leftrightarrow-20x-41=-6x+27\)

=>-14x=68

hay x=-34/7

 

4 tháng 8 2019

a) 10x(x - y)2 - 5(x - y)3 = [10x - 5(x - y)](x - y)2 = (10x - 5x + y)(x - y)2 = (5x + y)(x - y)2

b) -x2 - 10x - 25 = -(x2 + 10x + 52) = -(x + 5)2

c) 64x6y4 - 81x2y2 = (8x3y2)2 - (9xy)2 = (8x3y2 + 9xy)(8x3y2 - 9xy)

d) x6 - y6 = (x3)2 - (y3)2 = (x3 - y3)(x3 + y3) = (x - y)(x2 + xy + y2)(x + y)(x2 - xy + y2)

e)1/8x3 - 3/4x2y + 3/2xy2 - y3 = (1/2x)3 - 3.(1/2x)2y + 3.1/2xy2 - y3 = (1/2x - y)3

f) (3x + 1)2 - (x - 1)2 = (3x + 1 + x - 1)(3x + 1 - x + 1) =  4x(2x + 2) = 8x(x + 1)