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\(\left(x-3\right)\left(x-12\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x-12=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=12\end{cases}}\)
\(\Rightarrow x\in\left\{3;12\right\}\)
\(\left(x^2-81\right)\left(x^2+9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2-81=0\\x^2+9=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=9\\x\in\varnothing\end{cases}}\Leftrightarrow x=9\)
\(\Rightarrow x=9\)
\(\left(x-4\right)\left(x+2\right)< 0\)
\(\Rightarrow\hept{\begin{cases}x-4\\x+2\end{cases}}\)trái dấu
\(TH1:\hept{\begin{cases}x-4>0\\x+2< 0\end{cases}}\Leftrightarrow\hept{\begin{cases}x>4\\x< -2\end{cases}}\Leftrightarrow x\in\varnothing\)
\(TH2:\hept{\begin{cases}x-4< 0\\x+2>0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x< 4\\x>-2\end{cases}}\Leftrightarrow x\in\left\{-1;0;1;2;3\right\}\)
Vậy \(x\in\left\{-1;0;1;2;3\right\}\)
Ta có :
\(S=2+2^2+.....+2^{100}\)
\(\Rightarrow2S=2^2+2^3+....+2^{101}\)
\(\Rightarrow2S-S=\left(2^2+2^3+.....+2^{101}\right)-\left(2+2^2+....+2^{100}\right)\)
\(\Rightarrow S=2^{101}-2\)
\(\frac{1024}{\left(17x2^5+15x2^5\right)}=\frac{2^{10}}{32x2^5}=\frac{2^{10}}{2^5.2^5}=\frac{2^{10}}{2^{10}}=1\) (1024=210; 32=25)
chị giúp nhưng phải k cho c nhé.
\(1024:\left(17x2^5+15x2^5\right)\)
\(=\)\(1024:\left[\left(17+15\right)x2^5\right]\)
\(=1024:\left(32x2^5\right)\)
\(=2^{10}:\left(2^5x2^5\right)\)
\(=2^{10}:2^{10}=1\)
\(2.\left(2x-\frac{4}{3}\right)^2+\frac{1}{4}=\frac{1}{2}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)^2=\frac{1}{2}-\frac{1}{4}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)^2=\frac{1}{4}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)=\sqrt{\frac{1}{4}}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)=\frac{1}{2}\)
\(\Rightarrow2x=\frac{1}{2}+\frac{4}{3}\)
\(\Rightarrow2x=\frac{11}{6}\)
\(\Rightarrow x=\frac{11}{6}\div2\)
\(\Rightarrow x=\frac{11}{6}\times\frac{1}{2}\)
\(\Rightarrow x=\frac{11}{12}\)
\(125^3.25^4=25^9.25^4=25^{13}\)
\(16^2.64^5=4^4.4^{15}=4^{19}\)
3/7 + 1/2 - 17/7 +3/2
=(1/2+3/2) + (3/7-17/7)
=2+-2
=0