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\(x\times\frac{5}{9}=-\frac{5}{3}\)
\(x=-\frac{5}{3}\div\frac{5}{9}\)
\(x=-3\)
Vậy \(x=-3\)
\(x.\frac{5}{9}=\frac{-5}{3}\)
\(x=\frac{-5}{3}:\frac{5}{9}\)
\(x=\frac{-5}{3}.\frac{9}{5}\)
\(x=-3\)
học tốt
\(x\times\frac{5}{9}=-\frac{5}{3}\)
\(x=-\frac{5}{3}\div\frac{5}{9}\)
\(x=-3\)
Vậy \(x=-3\)
a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)
(\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)
- \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)
\(x\) = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))
\(x=\) - \(\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)
3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)
3\(x\) - 3,7 = - \(\dfrac{19}{2}\)
3\(x\) = - \(\dfrac{19}{2}\) + 3,7
3\(x\) = - \(\dfrac{29}{5}\)
\(x\) = - \(\dfrac{29}{5}\) : 3
\(x\) = - \(\dfrac{29}{15}\)
Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\)
a) \(x=\dfrac{-2}{7}+\dfrac{9}{7}=1\)
b) \(\dfrac{x}{3}=\dfrac{2}{5}+\dfrac{-4}{3}\)
\(\dfrac{x}{3}=\dfrac{-14}{15}\)
\(\Rightarrow x=\dfrac{3.-14}{15}=\dfrac{-14}{5}\)
\(x=\dfrac{-2}{7}+\dfrac{9}{7}\)
\(x=1\)
c) (x + 9 - 17) - 24 = 11 - (x + 7)
(x + 8) - 24 = 11 - (x + 7)
(x + 8) - 24 = 11 - x - 7
x-8-24=11-x-7
x-8-24=4-x
x -32 = 4 -x
x + x -32 =4
x + x = 4 +32
2x=36
x=18
a) -5x - 25 = 3x + 23
-5x - 32 = 3x + 8
-5x - 3x - 32 = 8
-5x - 3x = 8 +32
-8x = 8+32
-8x = 40
x= -5
2^3.x+3^2.x=51
\(\Rightarrow\)8.x+9.x=51
\(\Rightarrow\)x.(8+9)=51
\(\Rightarrow\)x.17=51
\(\Rightarrow\)x=51/17
\(\Rightarrow\)x=3
\(2^3x+3^2x=51\)
\(\Leftrightarrow8x+9x=51\)
\(\Leftrightarrow\left(8+9\right)x=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=51:17\)
\(\Leftrightarrow x=3.\)
Vậy \(x=3.\)
X. (X-9) =0
=> X=0 hoặc X-9=0
<=> X =0 hoặc X=-9
Vậy X = 0 hoặc -9...
Bài làm
@Hữu Nam: chuyển sang phải lại 9 chứ k pk âm 9 nha bn . Như z nè:
x( x - 9 ) = 0
<=> x = 0 hoặc x - 9 = 0
<=> x = 0 hoặc x = 9
Vậy x = 0 hoặc x = 9
# học tốt #
Lời giải:
$\frac{x^2}{3}=\frac{9}{x}$
$\Rightarrow x^2.x=3.9$
$\Rightarrow x^3=27=3^3$
$\Rightarrow x=3$