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\(x\div0,25-x\times0,5=4,2\)
\(\Leftrightarrow x\times4-x\times0,5=4,2\)
\(\Leftrightarrow x\times\left(4-0,5\right)=4,2\)
\(\Leftrightarrow x\times3,5=4,2\)
\(\Leftrightarrow x=1,2\)
Vậy \(x=1,2\)
x : 0,25 - x . 0,25 = 4,2 ( . là dấu nhân )
\(x\ .\ ( 4 - \ {1\over 4}) = 4,2\)
\(x \ . \ 3,75 = 4,2\)
\(x = 1,12\)
15-(2,5.x+3).0,5=7,5
15-(2,5.x+3)=7,5:0,5
15-(2,5.x+3)=15
(2,5.x+3)=15-15
(2,5.x+3)=0
2,5.x=0-3
2,5.x=-3
X=-3:2,5
x=-1,2
15 - ( 2,5 x X + 3 ) x 0,5 =7,5
X = [ 15 - ( 7,5 : 0,5 -3 )] : 2,5
X = [ 15 - ( 15 - 3 )] : 2,5
X = [ 15 - 12 ] : 2,5
X = 3 : 2,5
X = 1,2
X =
X x 97 = 349,2 + 1,25
X x 97 = 350,45
X = 350,45 : 97
X = ? (sai đề)
b) X x (0,25 + 0,75 + 1 ) = 10,8
X x 2 = 10,8
X = 10,8 : 2
X = 5,4
35 x 11 x 0,1 x 0,25 x 100 x (3 : 0,4 - 7,5)
= 35 x 1,1 x 25 x 0
= 38,5 x 25 x 0
= 962,5 x 0
= 0
\(180-\left(x-45\right)\div2=120\)
\(\left(x-45\right)\div2=180-120\)
\(\left(x-45\right)\div2=60\)
\(x-45=60\times2\)
\(x-45=120\)
\(x=120+45\)
\(x=165\)
\(\left(2009-x\right)\div29+32=100\)
\(\left(2009-x\right)\div29=100-32\)
\(\left(2009-x\right)\div29=68\)
\(2009-x=68\times29\)
\(2009-x=1972\)
\(x=2009-1972\)
\(x=37\)
\(\left(x-2\right)\times3-270\div45=120\)
\(\left(x-2\right)\times3-6=120\)
\(\left(x-2\right)\times3=120+6\)
\(\left(x-2\right)\times3 =126\)
\(x-2=126\div3\)
\(x-2=42\)
\(x=42+2\)
\(x=44\)
\(\left(x+0,2\right)+\left(x+0,7\right)+\left(x+1,2\right)+...+\left(x+4,2\right)+\left(x+4,7\right)=65,5\)
\(\left(x+x+x+..+x+x\right)+\left(0,2+0,7+1,2+...+4,2+4,7\right)=65,5\)
\(10x+\frac{\left(0,2+4,7\right)\times10}{2}=65,5\)
\(10x+24,5=65,5\)
\(10x=65,5-24,5\)
\(10x=41\)
\(\Rightarrow x=4,1\)
a)\(\frac{11}{14}-\frac{x}{7}=\frac{23}{14}\)
\(\Leftrightarrow11-2x=23\)
\(\Leftrightarrow2x=-12\)
\(\Leftrightarrow x=-6\)
b)7,75-(0,5x-0,2)=5
<=>7,95-0,5x=5
<=>0,5x=2,95
<=>x=5,9
c)17,5-x=45/15
<=>x=14
câu a) bạn chưa học âm thì mình bó tay chứ cái câu a) x ra âm là chắc
nhớ tíck mình đấy
a) 11/14-x/7=23/14
x/7= 23/14-11/14
x/7=6/7
Vậy x=7
b) 7.75-(0.5x X -0.2)=5
0.5xX-0.2= 7.75-5
0.5xX-0.2=2.75
0.5xX =2.75+0.2
0.5xX =2.95
X = 2.95:0.5
X = 5.9
c) 17.5-x=45/15
17.5-x=3
x=17.5-3
x=14.5
\(\frac{1}{5.7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+...+\frac{1}{2009\cdot2011}+\frac{1}{x}=\frac{1}{5}\cdot0,5\)
\(=\frac{7-5}{5\cdot7}+\frac{9-7}{7\cdot9}+\frac{11-9}{9\cdot11}+...+\frac{2011-2009}{2009\cdot2011}+\frac{1}{x}=\frac{1}{10}\)
\(=\left[\frac{1}{2}\cdot\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{2009}-\frac{1}{2011}\right)\right]+\frac{1}{x}=\frac{1}{10}\)
\(=\left[\frac{1}{2}\cdot\left(\frac{1}{5}-\frac{1}{2011}\right)\right]+\frac{1}{x}=\frac{1}{10}\)
\(=\left(\frac{1}{2}\cdot\frac{2006}{10055}\right)+\frac{1}{x}=\frac{1}{10}\)
\(=\frac{1003}{10055}+\frac{1}{x}=\frac{1}{10}\)
\(\Rightarrow\frac{1}{x}=\frac{1}{10}-\frac{1003}{10055}\)
\(\frac{1}{x}=\frac{1}{4022}\)
\(\Rightarrow x=1\div\frac{1}{4022}=4022\)
=>x(0,2+0,5+0,25+1)=45
=>x*1,95=45
=>x=300/13