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\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\) <=> \(\frac{6,09-5,25x}{\left(\frac{95}{9}-\frac{29}{4}\right).\frac{36}{17}}=\frac{3}{4}\)<=> \(\frac{6,09-5,25x}{\frac{119}{36}.\frac{36}{17}}=\frac{3}{4}\)
<=> \(\frac{6,09-5,25x}{7}=\frac{3}{4}\)<=> 4(6,09-5,25x)=21 <=> 24,36-21x=21
=> 21x=3,36 => x=3,36:21 => x=0,16
Đáp số: x=0,16
Ta có :\(\frac{x}{2}=\frac{36}{x+1}\)
=> x.(x+1)=2.36
=> x.(x+1)=72
mà 72= 8.9
=> x.(x+1)= 8.(8+1)
=> x = 8
Vậy x = 8
\(\frac{2}{x}=\frac{x}{8}\)
\(\Rightarrow2.8=x.x\Rightarrow16=x^2\)
\(\Rightarrow\)x = 4 hoặc x =-4
\(2.x=\frac{1+2+3+...+9}{1-2+3-4+5-6+7-8+9}+\frac{25.150-60.5+20.75}{1+2+3+...+99}\)
\(2.x=\frac{\left(9+1\right).9:2}{\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+\left(7-8\right)+9}+\frac{2.3.5^2.\left(5^2-2+2.5\right)}{\left(1+99\right).99:2}\)
\(2.x=\frac{45}{\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+9}+\frac{2.3.5^2.33}{100.99.\frac{1}{2}}\)
\(2x=\frac{45}{5}+\frac{50.99}{50.2.99.\frac{1}{2}}=9+\frac{1}{2.\frac{1}{2}}=9+1=10\)
=> 2x = 10
x = 5
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
\(\Rightarrow\frac{x-10}{30}-3+\frac{x-14}{43}-2+\frac{x-5}{95}-1+\frac{x-148}{8}+6=0\)
\(\Rightarrow\frac{x-100}{30}+\frac{x-100}{43}+\frac{x-100}{95}+\frac{x-100}{8}=0\)
\(\Rightarrow\left(x-100\right)\left(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\right)=0\)
mà \(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\ne0\)
=> x - 100 = 0 => x = 100
Vậy x = 100
Ta có : x+75%.x=\(\frac{-5}{8}\)
=> x+0,75.x=\(\frac{-5}{8}\)
=> x+\(\frac{3}{4}\).x=\(\frac{-5}{8}\)
=> x.(1+\(\frac{3}{4}\))=\(\frac{-5}{8}\)
=> x.\(\frac{7}{4}\)=\(\frac{-5}{8}\)
=> x=\(\frac{-5}{14}\)
Vậy x=\(\frac{-5}{14}\)
Các bạn hãy tk cho mk nha !!!