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\(\Rightarrow x+\frac{x}{7}=\frac{16}{35}\)
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Trả lời
\(\frac{x}{7}=\frac{x-16}{35}\)
\(\Leftrightarrow35x=7.\left(x-16\right)\)
\(\Leftrightarrow35x=7x-112\)
\(\Leftrightarrow28x=-112\)
\(\Leftrightarrow x=-4\)
Vậy \(x=-4\)
x/7 = (x + 16)/35
(5 * x)/(5 * 7) = (x + 16)/35
(5 * x)/35 = (x + 16)/35
=> 5 * x - x = 16
4 * x = 16
x = 16 : 4
x = 4
\(\frac{x}{7}=\frac{x+16}{35}\)
\(\Leftrightarrow35x=7\left(x+16\right)\)
\(\Leftrightarrow35x=7x+112\)
\(\Leftrightarrow35x-7x=112\)
\(\Leftrightarrow28x=112\)
\(\Leftrightarrow x=4\)
a. (5.x + 3) : 4 – 16 = 6
(5.x + 3) : 4 = 22
(5.x + 3) = 88
5.x = 85
x = 13
b. 7(23 – 3.x) : 2 – 35 = 35
7(23 – 3.x) : 2 = 70
7(23 – 3.x) = 35
7 . 3.x = 12
7.x = 4
x = 4/7
a.) (5.x + 3) : 4 – 16 = 6
=> (5.x + 3) : 4 = 22
=> 5.x + 3 = 88
=> 5x = 85
=> x = 17
b) 7(23 – 3.x) : 2 – 35 = 35
=> 7(23 – 3.x) : 2 = 70
=>7(23 – 3.x) = 140
=> 23 – 3.x = 20
=> 3x = 3
=> x = 1
Lời giải:
$\frac{x}{7}=\frac{x+16}{35}$
$\Rightarrow 35x=7(x+16)$
$\Rightarrow 35x-7x=112$
$\Rightarrow 28x=112$
$\Rightarrow x=4$
\(\frac{x}{7}=\frac{5x}{35}=\frac{x+16}{35}\)=> 5x = x + 16 => 4x = 16 => x = 16 : 4 = 4
\(\frac{x}{7}=\frac{x+16}{35}\)
\(\Leftrightarrow x\cdot35=7\left(x+16\right)\)
\(\Leftrightarrow35x=7x+112\)
\(\Leftrightarrow35x-7x=112\)
\(\Leftrightarrow28x=112\)
\(\Leftrightarrow x=4\)
Vậy x = 4
\(\frac{8}{x}=\frac{7}{x-16}\)
\(\Leftrightarrow8\left(x-16\right)=x\cdot7\)
\(\Leftrightarrow8x-128=7x\)
\(\Leftrightarrow8x-7x=128\)
\(\Leftrightarrow x=128\)
Vậy x = 128
a,\(\frac{x}{7}=\frac{x+16}{35}< =>\frac{5x}{35}=\frac{x+16}{35}\)
\(< =>5x=x+16\)
\(< =>4x=16< =>x=4\)
b,\(\frac{8}{x}=\frac{7}{x-16}\)\(< =>8x-128=7x\)
\(< =>x=128\)
\(\frac{x}{7}=\frac{x+16}{35}\Leftrightarrow35x=7\left(x+16\right)\)
\(\Leftrightarrow35x-7x=112\)
\(\Leftrightarrow28x=112\Leftrightarrow x=4\)
\(\left(x-2\right)^2=25\Leftrightarrow x-2=5\)
\(\Leftrightarrow x=7\)