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\(\frac{1}{6}=\frac{1}{8}+\frac{1}{24}=\frac{1}{9}+\frac{1}{18}\)
\(\frac{3}{35}=\frac{1}{35}+\frac{1}{35}+\frac{1}{35}=\frac{1}{70}+\frac{1}{14}\)
Nếu đúng thì k mk nha
TL:
\(\frac{12}{100}\)= 0,12
\(\frac{5}{100}\)= 0,05
\(\frac{306}{1000}\)= 0,306
-HT-
a)\(\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
b)\(\frac{7}{12}=\frac{1}{2}+\frac{1}{12}=\frac{1}{3}+\frac{1}{4}\)
c)\(\frac{7}{8}=\frac{1}{8}+\frac{6}{8}\)
\(\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{12}=\frac{1}{3}+\frac{1}{4}\)
\(\frac{15}{16}=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(\frac{3}{18}=\frac{1}{18}+\frac{2}{18}=\frac{1}{18}+\frac{1}{9}\)
\(\frac{13}{27}=\frac{1}{27}+\frac{12}{27}=\frac{1}{27}+\frac{3}{27}+\frac{9}{27}=\frac{1}{27}+\frac{1}{9}+\frac{1}{3}\)
a) \(\frac{5}{6}=\frac{1}{3}+\frac{1}{2}\)
b) \(\frac{7}{12}=\frac{1}{12}+\frac{1}{2}\)
c) \(\frac{7}{8}=\frac{1}{2}+\frac{3}{8}\)
\(\frac{5}{6}=\frac{3}{6}+\frac{2}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{12}=\frac{6}{12}+\frac{1}{12}=\frac{1}{2}+\frac{1}{12}\)
\(=\frac{4}{12}+\frac{3}{12}=\frac{1}{3}+\frac{1}{4}\)
\(\frac{7}{8}=\frac{4}{8}+\frac{2}{8}+\frac{1}{8}=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\)
\(\dfrac{11}{16}\) = \(\dfrac{1}{16}\) + \(\dfrac{10}{16}\) = \(\dfrac{1}{16}\) + \(\dfrac{2+8}{2\times8}\) = \(\dfrac{1}{16}\) + \(\dfrac{2}{2\times8}\) + \(\dfrac{8}{2\times8}\) = \(\dfrac{1}{16}\) + \(\dfrac{1}{8}\)+ \(\dfrac{1}{2}\)
\(\dfrac{5}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{4}{12}\) = \(\dfrac{1}{12}\) + \(\dfrac{4}{3\times4}\) = \(\dfrac{1}{12}\) + \(\dfrac{1}{3}\)