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\(3\cdot9\cdot81\cdot729=3^1\cdot3^2\cdot3^4\cdot3^6=3^{1+2+4+6}=3^{13}\)
a) 256. 1253
= (52)6. (53)3
= 512. 56
= 512+6
= 518
b) 6255: 257
= (54)5: (52)7
= 520: 514
=520-14
=56
c) 123.33
= (12.3)3
=363 (=66)
a) \(25^6.125^3=\left(5^2\right)^6.\left(5^3\right)^3=5^{12}.5^9=5^{21}\)
b) \(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)
c) \(12^3.3^3=\left(12.3\right)^3=36^3\)
a) \(3^5.4^5=\left(3.4\right)^5=12^5\)
b) \(8^5.2^3=\left(2^3\right)^5.2^3=2^{15}.2^3=2^{15+3}=2^{18}\)
\(3^5.4^5=3+4^5=7^5\)
\(8^5.2^3=8+2^{5+3}=10^8\)
Ko biết nữa !
\(A=1+2+2^2+2^3+...+2^{100}\)
\(\Rightarrow2A=2+2^2+2^3+...+2^{200}+2^{201}\)
\(2A-A=A=\left(2+2^2+2^3+...+2^{201}\right)-\left(1+2+2^2+2^3+...+2^{200}\right)\)
\(\Rightarrow A=2^{201}-1\Rightarrow A+1=2^{201}-1+1=2^{201}\)
ta có
A= 1+2+22+23+...+2200
2A= 2+22+23+...+2201
2A-A=(2+22+23+...+2201)-(1+2+22+23+...+2200)
A=2201 - 1
A+1=2201
5^5 x 3^4 va 3^4x7^3x2
a) 5x5x3x15x25x9 =5x5x3x3x5x5x5x3x3= 5^5x3^4
b) 9x21x2x3x49 = 3x3x2x3x49 = 3^3x2x49