Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1. \(x^2-2x+2+4y^2+4y\)
\(=\left(x^2-2x+1\right)+\left(4y^2+4y+1\right)\)
\(=\left(x-1\right)^2+\left(2y+1\right)^2\)
2. \(4x^2-4x+y^2+2y+2\)
\(=\left(4x^2-4x+1\right)+\left(y^2+2y+1\right)\)
\(=\left(2x-1\right)^2+\left(y+1\right)^2\)
3. \(4x^2+4x+4y^2+4y+2\)
\(=\left(4x^2+4x+1\right)+\left(4y^2+4y+1\right)\)
\(=\left(2x+1\right)^2+\left(2y+1\right)^2\)
4. \(4x^2+y^2+12x+4y+13\)
\(=\left(4x^2+12x+9\right)+\left(y^2+4y+4\right)\)
\(=\left(2x+3\right)^2+\left(y+2\right)^2\)
\(x^2-2x+2+4y^2+4y\)
\(=\left(x^2-2x+1\right)+\left(4y^2+4y+1\right)\)
\(=\left(x-1\right)^2+\left(2y+1\right)^2\)
\(4x^2-4x+y^2+2y+2\)
\(=\left(2x-1\right)^2+\left(y+1\right)^2\)
bình phương tổng chứ
b, B= x^2+ 2xy+y^2 +4y+4
= x^2+2xy+y^2+y^2+4y+4
=(x+y)^2+(y+2)^2
c, C= 2x^2+6xy+9y^2+2x+1
= x^2+6xy+9y^2+x^2+2x+1
= (x+3)^2+(x+1)^2
d, D= x(x+2) +(x+1)(x+3) +2
= x^2+2x+x^2+3x+x+3+2
= x^2+2x+1+x^2+4x+4
= (x+1)^2+(x+2)^2
e, E= x^2-2xy+2y^2+2y+1
= x^2-2xy+y^2+y^2+2y+1
= (x-y)^2+(y+1)^2
f, F= 4x^2-12xy+10y^2+4y+4
=4x^2-12xy+9y^2+y^2+4y+4
=(2x-3y)^2+(y+2)^2
g, G=2x^2+4xy+4y^2+4x+4
=x^2+4xy+4y^2+x^2+4x+4
=(x+2y)^2+(x+2)^2
Xong r.... dài quá...mới hè lớp 7 nên có j bỏ qua ak
a) ( 2x + 1 )2 + 10( 2x + 1 ) + 25
= ( 2x + 1 )2 + 2.( 2x + 1 ).5 + 52
= [ ( 2x + 1 ) + 5 ]2
= ( 2x + 1 + 5 )2
= ( 2x + 6 )2
b) x2 + 2x( y - 2 ) + y2 - 4y + 4
= x2 + 2x( y - 2 ) + ( y2 - 4y + 4 )
= x2 + 2x( y - 2 ) + ( y - 2 )2
= [ x + ( y - 2 ) ]2
= ( x + y - 2 )2
c) x2 + 12x + 40 + y2 + 4y
= ( x2 + 12x + 36 ) + ( y2 + 4y + 4 )
= ( x + 6 )2 + ( y + 2 )2 ( cấy ni không viết được ;-; )
d) x2 - 8x - 20 - y2 - 12y
= ( x2 - 8x + 16 ) - ( y2 + 12y + 36 )
= ( x - 4 )2 - ( y + 6 )2
= [ ( x - 4 ) - ( y + 6 ) ][ ( x - 4 ) + ( y + 6 ) ]
= ( x - 4 - y - 6 )( x - 4 + y + 6 )
= ( x - y - 10 )( x + y + 2 )
e) x2 + y2 + 4x + 4y + 2( x + 2 )( y + 2 ) + 8
= ( x2 + 4x + 4 ) + 2( x + 2 )( y + 2 ) + ( y2 + 4y + 4 )
= ( x + 2 )2 + 2( x + 2 )( y + 2 ) + ( y + 2 )2
= [ ( x + 2 ) + ( y + 2 ) ]2
= ( x + 2 + y + 2 )2
= ( x + y + 4 )2
\(1,\)\(4x^2-4x+y^2+2y+2\)
\(=4x^2+4x+1+y^2+2y+1\)
\(=\left[\left(2x\right)^2-2.2x+1\right]+\left(y^2+2.y.1+1^2\right)\)
\(=\left(2x-1\right)^2+\left(y+1\right)^2\)
\(2,\)\(a^2-4ab+5b^2-4bc+4c^2\)
\(=a^2-4ab+4b^2+b^2-4bc+4c^2\)
\(=\left[a^2-2.a.2b+\left(2b\right)^2\right]+\left[b^2-2.b.2c+\left(2c\right)^2\right]\)
\(=\left(a-2b\right)^2+\left(b-2c\right)^2\)
\(3,\)\(16x^2+5+8x-4y+y^2\)
\(=16x^2+8x+1+y^2-4y+4\)
\(=\left[\left(4x\right)^2+2.4x.1+1^2\right]+\left[y^2-2.y.2+2^2\right]\)
\(=\left(4x+1\right)^2+\left(y-2\right)^2\)
a, Đề sai bạn ơi phải là cộng 16 chứ không phải cộng 4
b,B= (x-2y+1)^2
\(a.=\left(2x\right)^2-2.2x.2y+\left(2y\right)^2=\left(2x-2y\right)^2\)
\(b.=\left(3x\right)^2-2.3x.2+2^2=\left(3x-2\right)^2\)
a. 4x2+4y2-8xy=(2x)2+(2y)2-8xy
=(2x-2y)2
b.9x2-12x+4=(3x)2-12x+22
=(3x-2)2
c.xy2+1/4x2y4+1=xy2+(1/2xy2)2+1
=(1/2xy2+2)2
