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\(a.x^2-4x+4+y^2+2y+1\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
\(b.x^2+10x+25+x^2-2xy+y^2\)
\(=\left(x+5\right)^2+\left(x-y\right)^2\)
......................?
mik ko biết
mong bn thông cảm
nha ................
a: \(x^2-4x+y^2+2y+5\)
\(=x^2-4x+4+y^2+2y+1\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
b: \(2x^2+y^2-2xy+10x+25\)
\(=x^2+y^2-2xy+x^2+10x+25\)
\(=\left(x-y\right)^2+\left(x+5\right)^2\)
c: \(2x^2+2y^2\)
\(=\left(x^2+2xy+y^2\right)+\left(x^2-2xy+y^2\right)\)
\(=\left(x+y\right)^2+\left(x-y\right)^2\)
a) \(x^2+10x+26+y^2+2y\)
\(=\left(x^2+10x+25\right)+\left(y^2+2y+1\right)\)
\(\left(x+5\right)^2+\left(y+1\right)^2\)
b) \(x^2-2xy+2y^2+2y+1\)
\(=\left(x^2-2xy+y^2\right)+\left(y^2+2y+1\right)\)
\(=\left(x-y\right)^2+\left(y+1\right)^2\)
c) \(z^2-6z+13+t^2+4t\)
\(=\left(z^2-6x+9\right)+\left(t^2+4t+4\right)\)
\(=\left(z-3\right)^2+\left(t+2\right)^2\)
d) \(4x^2-2z^2-2xz-2z+1\)
\(=\left(4x^2-4xz+z^2\right)+\left(z^2-2z+1\right)\)
\(=\left(2x-z\right)^2+\left(z-1\right)^2\)
a) x2+10x+26+y2+2y
=x2+10x+25+y2+2y+1
=(x+5)2+(y+1)2
b) z2-6z+5-t2-4t
=z2-6z+9-t2-4t-4
=(z-3)2-(t2+4t+4)
=(z-3)2-(t+2)2
c)x2-2xy+2y2+2y+1
=x2-2xy+y2+y2+2y+1
=(x-y)2+(y+1)2
d) 4x2-12x-y2+2y+8
=4x2-12x+9-y2+2y-1
=(2x-3)2-(y2-2y+1)
=(2x-3)2-(y-1)2
a, x2-4x+5+y2+2y
=(x2-4x+4)+(y2+2y+1)
=(x-2)2+(y+1)2
b, 2x2+y2-2xy+10x+25
=(x2-2xy+y2)+(x2+10+25)
=(x-y)2+(x+5)2
c, 2x2+2y2=2(x2+y2)
a.) \(A=x^2+y^2+1+2xy+2x+2y=\left(x+y+1\right)^2.\)
b.) \(B=u^2+v^2+2u+2v+2\left(u+1\right)\left(v+1\right)+2=u^2+2u+1+2\left(u+1\right)\left(v+1\right)+v^2+2v+1\)
\(B=\left(u+1\right)^2+2\left(u+1\right)\left(v+1\right)+\left(v+1\right)^2=\left(u+1+v+1\right)^2=\left(u+v+2\right)^2\)
Giả sử số tự nhiên a chia cho 7 dư 3. CMR a chia cho 7 dư 2
\(x^2+2y^2+2xy-2y+2\)
\(=\left(\frac{x^2}{2}+2xy+2y^2\right)+\left(\frac{x^2}{2}-2x+2\right)\)
\(=\left(\frac{x}{\sqrt{2}}+\sqrt{2}y\right)^2+\left(\frac{x}{\sqrt{2}}-\sqrt{2}\right)^2\)
a) 2x2 + y2 - 2xy + 10x + 25
= (x2 + y2 - 2xy) + (x2 + 10x + 25)
= (x - y)2 + (x + 5)2
các bn xem đúng ko nhé mk làm bừa nên lên olm hỏi lại mọi người giúp giùm câu b) nha!!
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