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- a.(3x)2=1/243x33=1/9
3x=1/3 hoặc 3x=-1/3 ( vế 2 ko có x thỏa mãn)
suy ra x=3-1
b.(5x+1)=\(\sqrt{\frac{36}{49}}\)\(\Rightarrow\)5x+1=\(\frac{4}{7}\)hoặc 5x+1=\(\frac{-4}{7}\) | |
\(\Rightarrow\)x=\(\frac{-3}{35}\)hoặc x=\(\frac{-11}{35}\) | |
c.\(\frac{6}{4}\)-10x = \(\frac{4}{5}\)-3x chuyển vế :\(\frac{6}{4}\)-\(\frac{4}{5}\)= -3x + 10x \(\frac{7}{10}\)=7x \(\Rightarrow\)x =\(\frac{7}{10}\):7 \(\Rightarrow\)x= \(\frac{1}{10}\) |
Bài 1 :
a. \(\left|x-\frac{1}{3}\right|< \frac{5}{2}\)
TH1 : nếu \(\left|x-\frac{1}{3}\right|>0\)
\(x-\frac{1}{3}< \frac{5}{3}\)
\(x< 2\)
TH2 : nếu \(\left|x-\frac{1}{3}\right|< 0\)
\(\frac{1}{3}-x< \frac{5}{3}\)
\(x>-\frac{4}{3}\)
Bài 2 :
a. \(\left(x-2\right)^2=1\)
\(\left(x-2\right)^2-1=0\)
\(\left(x-2-1\right)\left(x-2+1\right)=0\)
\(\left(x-3\right)\left(x-1\right)=0\)
\(\left[\begin{array}{nghiempt}x-3=0\\x-1=0\end{array}\right.\)
\(\left[\begin{array}{nghiempt}x=3\\x=1\end{array}\right.\)
a) (x + 1/2)^2 = 1/16
=> (x + 1/2)^2 = (1/4)^2 hoặc (x + 1/2)^2 = (-1/4)^2
=> x + 1/2 = 1/4 hoặc x + 1/2 = -1/4
* x + 1/2 = 1/4
x = 1/4 - 1/2
x = -1/4
* x + 1/2 = -1/4
x = -1/4 - 1/2
x = -3/4
Vậy x = -1/4 hoặc x = -3/4
b) 2^x+2 - 2^x = 9^6
=> 2^x . 2^2 - 2^x = 9^6
=> 2^x . (2^2 - 1) = 9^6
=> 2^x . (4 - 1) = 9^6
=> 2^x . 3 = (3^2)^6
=> 2^x . 3 = 3^12
=> 2^x = 3^12 : 3
=> 2^x = 3^11
Vì 3^11 không chia hết cho 2
=> Không có giá trị nào của x thõa mãn đề bài
c) (3^x)^2 : 3^3 = 1/243
=> 3^2x = 1/243 . 3^3
=> 3^2x = 1/243 . 27
=> 3^2x = 1/9
=> 3^2x . 9 = 1
=> 3^2x . 3^2 = 1
=> 3^2x+2 = 1
=> 3^2x+2 = 3^0
=> 2x + 2 = 0
=> 2x = 0 - 2
=> 2x = -2
=> x = -2 : 2
=> x = -1
a\(\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{4}\right)^2
\)
\(\Rightarrow x+\frac{1}{2}=\frac{1}{4}\)
\(\Leftrightarrow x=\frac{1}{4}-\frac{1}{2}\)
\(\Rightarrow x=\frac{-1}{4}\)
B1:
a)x=-3/5*9/25 =>x=-27/125
b)x=(4/7)6:(4/7)4 =>x=(4/7)2=16/49
c)(x/4)2=4:(x/2)
(x/4)2=8/x
x2/16=8/x2
x3=128
x=5,039
B2
M=23.10+22.10/23.4+22.11
=230+220/212+222
=230+28+222
=28(222+1+214)
=2
3^2.1/243.81^2.1/3^2
=9/243.81^2/3^2
=1/27.27^2/1
=27^2/27
=27
a, ( x-1)3= -27
=> x - 1 = -3
=> x = -2
b, ( 2x - 1)2=25
=> 2x - 1 = 5 hoặc 2x - 1 = -5
=> 2x = 6 hoặc 2x = -4
=> x = 3 hoặc x = -2
c, ( x - 3/4)2= ( 1/2)6
=> (x - 3/4)^2 = 1/64
=> x - 3/4 = 1/8 hoặc x - 3/4 = -1/8
=> x = 7/8 hoặc x = 5/8
d, 2 x + 2 x +2 = 80
=> 2^x + 2^x.4 = 80
=> 2^x(1 + 4) = 80
=> 2^x.5 = 80
=> 2^x = 16
=> x = 4
e, 4x + 4 x + 3 = 4160
=> 4^x(1 + 64) = 4160
=> 4^x.65 = 4160
=> 4^x = 64
=> x = 3
\(\left(-xy^3\right).\frac{5}{2}x^2-2x^3y.\frac{1}{4}x^2y^2\)
=\(\left(-xy^3-2x^3y\right).\frac{1}{4}x^2y^2.\frac{5}{2}x^2\)
=\(-3xy^3.\frac{1}{4}x^2y^2.\frac{5}{2}x^2\)
\(3^2\times\frac{1}{243}\times81^2\times\frac{1}{3^3}\)
Ta có :
\(=9\times\frac{1}{243}\times6561\times\frac{1}{27}\)
\(=\frac{1}{27}\times6561\times\frac{1}{27}\)
\(=243\times\frac{1}{27}\)
\(=9\)
ủng hộ mik nhé .
\(3^2.\frac{1}{243}.81^2.\frac{1}{3^3}\)
\(=3^2.\frac{1}{3^5}.\left(3^4\right)^2.\frac{1}{3^3}\)
\(=3^2.\frac{1}{3^5}.3^8.\frac{1}{3^3}\)
\(=3^2.3^8.\frac{1}{3^5}.\frac{1}{3^3}\)
\(=3^{10}.\frac{1}{3^8}\)
tíc mình nha