Question

[Nguyễn Thùy Linh]

Tính:

A = ( \(2^{17}\) + \(17^2\) ) . ( \(9^{15}\) - \(3^{15}\) ) . ( \(2^4\) -\(4^2\) ) 

B= \(\frac{2^{13}+2^5}{2^{10}+2^2}\)

C = \(\left(1^2+2^2+2^3+........+2020\right)^2.\left(65.111-13.15.37\right)\)

 D = \(\frac{1+2+3+.....+2020}{6+8+10+........+54}\)

E = \(\frac{25^{28}+25^{24}+25^{20}+.....+25^4+1}{25^{30}+25^{28}+25^{26}+.....+25^2+1}\)

Answer 1

[Liên Phạm]

A=0

B=8