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\(\frac{84}{100}-\frac{29}{100}+\frac{30}{100}=\frac{85}{100}=\frac{17}{20}\)
85793-36841+3826=52778
325.97+86.54+103.46=515.97
TL:
\(\frac{12}{100}\)= 0,12
\(\frac{5}{100}\)= 0,05
\(\frac{306}{1000}\)= 0,306
-HT-
a; A = \(\dfrac{4026\times2014+4030}{2013\times2016-2011}\)
A = \(\dfrac{2\times\left(2013\times2014+2015\right)}{2013\times2016-2011}\)
A = \(\dfrac{2\times\left(2013\times2016-2013\times2+2015\right)}{2013\times2016-2011}\)
A = \(\dfrac{2\times\left(2013\times2016-4026+2015\right)}{2013\times2016-2011}\)
A = \(\dfrac{2\times\left(2013\times2016-2011\right)}{2013\times2016-2011}\)
A = 2
=13/12x14/13x15/14x16/15x...x2006/2005x2007/2006x2008/2007
=2008/12
=502/3
A = 1\(\dfrac{1}{12}\) \(\times\) 1\(\dfrac{1}{13}\) \(\times\) 1\(\dfrac{1}{14}\) \(\times\) 1\(\dfrac{1}{15}\) \(\times\) ... \(\times\) 1\(\dfrac{1}{2005}\) \(\times\) 1\(\dfrac{1}{2006}\) \(\times\) 1\(\dfrac{1}{2007}\)
A = ( 1 + \(\dfrac{1}{12}\)) \(\times\) ( 1 + \(\dfrac{1}{13}\)) \(\times\) ( 1 + \(\dfrac{1}{14}\)) \(\times\)...\(\times\) ( 1 + \(\dfrac{1}{2006}\))\(\times\)(1+\(\dfrac{1}{2007}\))
A = \(\dfrac{13}{12}\) \(\times\) \(\dfrac{14}{13}\) \(\times\) \(\dfrac{15}{14}\) \(\times\) ...\(\times\) \(\dfrac{2007}{2006}\) \(\times\) \(\dfrac{2008}{2007}\)
A = \(\dfrac{13\times14\times15\times...\times2007}{13\times14\times15\times...\times2007}\) \(\times\) \(\dfrac{2008}{12}\)
A = 1 \(\times\) \(\dfrac{502}{3}\)
A = \(\dfrac{502}{3}\)
Ta có công thức tổng quát:
\(\dfrac{k}{n\cdot\left(n+k\right)}=\dfrac{1}{n}-\dfrac{1}{n+k}\)
\(a,A=\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{x\left(x+3\right)}\\ =\dfrac{1}{3}\left(\dfrac{3}{5\cdot8}+\dfrac{3}{8\cdot11}+...+\dfrac{3}{x\left(x+3\right)}\right)\\ =\dfrac{1}{3}\left(\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+...+\dfrac{1}{x}-\dfrac{1}{x+3}\right)\\ =\dfrac{1}{3}\cdot\left(\dfrac{1}{5}-\dfrac{1}{x+3}\right)\\ =\dfrac{1}{3}\cdot\dfrac{x-2}{5\left(x+3\right)}\\ =\dfrac{x-2}{15\left(x+3\right)}\)
Theo đề bài ta có:
\(A=\dfrac{101}{1540}\\ \Rightarrow\dfrac{x-2}{15\left(x+3\right)}=\dfrac{101}{1540}\\ \Rightarrow\dfrac{x-2}{x+3}=\dfrac{303}{308}\\ \Rightarrow\dfrac{x-2}{x+3}=\dfrac{305-2}{305+3}\\ \Rightarrow x=305\)
75/100 = 0,75
75% = 0,75
3/4 = 0,75
Rút gọn biểu thức còn :
0,75 + 0,73 x 29 + 0,75 x 30 + 0,75 x 40
= 0,75 x ( 29 + 1 + 30 + 40 )
= 0,75 x 100
= 75
đổi : \(\frac{75}{100}\)= 0,75 = 75% ; \(\frac{3}{4}\)=\(\frac{75}{100}\)=0,75=75% ; 0,75 = 75%
ta có : 75% + 75% x 29 + 75% x 30 + 75% x 40
= 75% x (29+30+40+1)
=75%x100
= 75
xin lỗi các bạn mình viết nhầm nhân thành cộng ở chỗ 40 mong các bạn thông cảm
các bạn k mình nhé thank you very much
bye bye
1 gấp 10 lần 1/10
1/10 : 1/100 = 10
1/100 : 1/1000 = 10
1 : 1/10 = 10
1/10 gấp 10 lần 1/100
1/100 gấp 10 lần 1/1000
k mình nha
a) 85793 - 36841 + 3826 = 48952 + 3826 = 52778
b) \(\dfrac{84}{100}-\dfrac{29}{100}+\dfrac{30}{100}\) = \(\dfrac{55}{100}+\dfrac{30}{100}\) = \(\dfrac{85}{100}\) =\(\dfrac{17}{20}\)
c) 325,97 + 86,54 + 103,46 = 412,51 + 103,46 = 515,97
a)\(85793-36841+3826=52778\)
b)\(\dfrac{84}{100}-\dfrac{29}{100}+\dfrac{30}{100}=\dfrac{84-29+30}{100}=\dfrac{85}{100}\)
c)\(325,97+86,54+103,46=515,97\)