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Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
a ) \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{\left(-11\right)}{70}\right|\)
=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)
=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{19}{70}\right|\)
=> \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\frac{19}{70}=\frac{3}{35}\)
=> \(\frac{2}{5}+x+\frac{3}{2}=\frac{3}{7}-\frac{3}{35}=\frac{12}{35}\)
=> \(\frac{2}{5}+x=\frac{12}{35}-\frac{3}{2}=-\frac{81}{70}\)
=> \(x=-\frac{81}{70}-\frac{2}{5}=-\frac{109}{70}\)
b) \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)
=> \(\frac{3}{4}x-6=\frac{5}{2}\)
=> \(\frac{3}{4}x=\frac{17}{2}\)
=> \(x=\frac{17}{2}:\frac{3}{4}=\frac{34}{3}\)
Câu c,d tự làm nhé
a. \(\frac{3}{7}-\left(\frac{2}{5}+x+\frac{3}{2}\right)=\frac{5}{14}-\left|\frac{4}{35}-\frac{-11}{70}\right|\)
\(\Rightarrow\frac{3}{7}-\left(\frac{19}{10}+x\right)=\frac{5}{14}-\left|\frac{4}{35}+\frac{11}{70}\right|\)
\(\Rightarrow\frac{3}{7}-\frac{19}{10}-x=\frac{5}{14}-\left|\frac{19}{70}\right|=\frac{5}{14}-\frac{19}{70}\)
\(\Rightarrow-\frac{103}{70}-x=\frac{3}{35}\)
\(\Rightarrow x=-\frac{103}{70}-\frac{3}{35}\)
\(\Rightarrow x=-\frac{109}{70}\)
b. \(\frac{3}{4}\left(x-8\right)=\frac{5}{7}\left(4-\frac{1}{2}\right)\)
\(\Rightarrow\frac{3}{4}\left(x-8\right)=\frac{5}{7}.\frac{7}{2}=\frac{5}{2}\)
\(\Rightarrow x-8=\frac{10}{3}\)
\(\Rightarrow x=\frac{34}{3}\)
c. \(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
\(\Rightarrow\frac{3}{2}-1+4x=\frac{2}{3}-7x\)
\(\Rightarrow\frac{1}{2}=\frac{2}{3}-7x-4x=\frac{2}{3}-11x\)
\(\Rightarrow11x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{66}\)
d. \(4\left(\frac{1}{2}-x\right)-5\left(x-\frac{3}{10}\right)=\frac{7}{4}\)
\(\Rightarrow2-4x-5x+\frac{3}{2}=\frac{7}{4}\)
\(\Rightarrow2-9x=\frac{1}{4}\)
\(\Rightarrow9x=\frac{7}{4}\)
\(\Rightarrow x=\frac{7}{36}\)
TL:
\(B=2x^2+y^2-2xy-2x+3\)
\(=\left(x^2-2xy+y^2\right)+(x^2-2x+1)+2\)
\(=\left(x-y\right)^2+\left(x-1\right)^2+2\ge2\forall x;y\)
\(D=\left(x+8\right)^4+\left(x+6\right)^4\ge0\forall x\)
Dấu"=" xảy ra<=> \(\hept{\begin{cases}\left(x+8\right)^4=0\\\left(x+6\right)^4=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=-8\\x=-6\end{cases}}\)
Bài 1:
a) -6x + 3(7 + 2x)
= -6x + 21 + 6x
= (-6x + 6x) + 21
= 21
b) 15y - 5(6x + 3y)
= 15y - 30 - 15y
= (15y - 15y) - 30
= -30
c) x(2x + 1) - x2(x + 2) + (x3 - x + 3)
= 2x2 + x - x3 - 2x2 + x3 - x + 3
= (2x2 - 2x2) + (x - x) + (-x3 + x3) + 3
= 3
d) x(5x - 4)3x2(x - 1) ??? :V
Bài 2:
a) 3x + 2(5 - x) = 0
<=> 3x + 10 - 2x = 0
<=> x + 10 = 0
<=> x = -10
=> x = -10
b) 3x2 - 3x(-2 + x) = 36
<=> 3x2 + 2x - 3x2 = 36
<=> 6x = 36
<=> x = 6
=> x = 5
c) 5x(12x + 7) - 3x(20x - 5) = -100
<=> 60x2 + 35x - 60x2 + 15x = -100
<=> 50x = -100
<=> x = -2
=> x = -2
A = 7/7.17 + 7/17.27 + 7/27.37 + ............ +7/1997.2007
A=7/10 ( 10/7.17 + 10/17.27 + 10/27.37 + ................+10/1997.2007)
A= 7/10 ( 1/7 -1/17 + 1/17 - 1/27 + 1/27 - 1/37 +...............+ 1/1997 - 1/2007)
A= 7/10 (1/7 - 1/2007)
A= 7/10 . 2000/14049
A=200/2007
bây h mk có vc rùi tích đúng nha tối mk lm típ cho
Giải:
a) Để đa thức có nghiệm
\(\Leftrightarrow x^2-64=0\)
\(\Leftrightarrow x^2=64\)
\(\Leftrightarrow x=\pm8\)
Vậy ...
d) Để đa thức có nghiệm
\(\Leftrightarrow x^2-81=0\)
\(\Leftrightarrow x^2=81\)
\(\Leftrightarrow x=\pm9\)
Vậy ...
h) Để đa thức có nghiệm
\(\Leftrightarrow x^2-6x=0\)
\(\Leftrightarrow\left(x-6\right)x=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)
Vậy ...
Các câu còn lại làm tương tự.
a, x\(^2\) - 64 = 0
\(\Rightarrow\) x\(^2\) = 0 + 64
= 64
= 8\(^2\)
\(\Rightarrow\) x = 8
Vậy nghiệm của \(x^2-64\) là 8
d, \(x^2-81\) = 0
\(\Rightarrow\) x\(^2\) = 81
= 9\(^2\)
\(\Rightarrow\) x = 9
vậy nghiệm của \(x^2-81\) là 9
a.|3+x|-|x-7|=9
<=>|3+x|=9+|x-7|
<=>3+x=9+(x-7) hoặc 3+x=9-(x-7)
Nếu 3+x=9+(x-7)
<=>3+x=9+x-7
<=>x+3=x+2 (loại)
Nếu 3+x=9-(x-7)
<=>3+x=9-(x-7)
<=>3x=16-x
<=>2x=13
<=>x=13/2
5\(x\) - 16 = 40 + \(x\)
5\(x\) - \(x\) = 40 + 16
4\(x\) = 56
\(x=56:4\)
\(x=14\)
Vậy \(x=14\)
b; 4\(x\) - 10 = 15 - \(x\)
4\(x\) + \(x\) = 15 +10
5\(x=25\)
\(x=25:5\)
\(x=5\)
Vậy \(x=5\)
c; -12 + \(x\) = 5\(x-20\)
5\(x\) = - 12 + \(x\) + 20
5\(x\) - \(x\) = - 12+ 20
4\(x\) = 8
\(x=\dfrac{8}{4}\)
\(x=2\)
Vậy \(x=2\)
d; \(x+15\) = 7 - 6\(x\)
6\(x\) = 7 - \(x\) - 15
6\(x\) + \(x\) = 7 - 15
7\(x\) = - 8
\(x=-\dfrac{8}{7}\)
Vậy \(x=-\dfrac{8}{7}\)
a) \((4{x^3}):( - 2{x^2})\\= [4: (- 2)].({x^3}:{x^2})\\ = - 2.{x^{3 - 2}}\\ = - 2x\);
b) \(( - 7{x^2}):(6x) \\= ( - 7:6).({x^2}:x) \\= - \dfrac{7}{6}.{x^{2 - 1}}\\ = - \dfrac{7}{6}.x\);
c) \(( - 14{x^4}):( - 8{x^3}) \\= ( - 14: - 8).({x^4}:{x^3})\\= \dfrac{7}{4}.{x^{4 - 3}} \\= \dfrac{7}{4}.x\).