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Question

tinh

( 3. 4 . 2¹⁶)² / 11 . 2¹³. 4¹¹-16⁹

KWS · Accepted Answer

$\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}$

$=\frac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}$

$=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}$

$=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{2^{36}.9}{2^{35}.9}=\frac{2^{36}}{2^{35}}=2$

Câu trả lời:

$\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}$

$=\frac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}$

$=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}$

$=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{2^{36}.9}{2^{35}.9}=\frac{2^{36}}{2^{35}}=2$